The acceleration due to gravity near the surface of the planet is 27.38 m/s².
<h3>
Acceleration due to gravity near the surface of the planet</h3>
g = GM/R²
where;
- G is universal gravitation constant
- M is mass of the planet
- R is radius of the planet
- g is acceleration due to gravity = ?
g = (6.626 x 10⁻¹¹ x 2.81 x 5.97 x 10²⁴) / (6371 x 10³)²
g = 27.38 m/s²
Thus, the acceleration due to gravity near the surface of the planet is 27.38 m/s².
Learn more about acceleration due to gravity here: brainly.com/question/88039
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The height of the table above the ground is 0.45 m.
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Horizontal velocity (u) = 3 m/s
- Time (t) = 0.3 s
- Acceleration due to gravity (g) = 10 m/s²
- Height (h) =?
<h3>How to determine the height </h3>
The height of the table can be obtained by using the following formula:
h = ½gt²
h = ½ × 10 × 0.3²
h = 5 × 0.09
h = 0.45 m
Thus, the height of the table is 0.45 m
Learn more about motion under gravity:
brainly.com/question/26275209
<span>To find the gravitational potential energy of an object, we can use this equation:
GPE = mgh
m is the mass of the object in kg
g = 9.80 m/s^2
h is the height of the object in meters
GPE = mgh
GPE = (0.700 kg) (9.80 m/s^2) (1.5 m)
GPE = 10.3 J
The gravitational potential energy of this can is 10.3 J</span>
Answer:
Potential, Kinetic and Chemical energy.
Explanation:
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