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Anna007 [38]
4 years ago
14

1. A rocket is fired vertically from the launch pad with a

Physics
1 answer:
zavuch27 [327]4 years ago
7 0

Answer:

Max height= 36000 meters

Total Time = 120 seconds

Explanation:

0 = U - at

U = at

U= 20*60

U= 1200 m/s

MAX altitude would be

(U²Sin²tita)/2g

Max height= 1200² *( SIN90)²/(2*20)

Time of FLIGHT

2 * 1200/20

2400/20

120 sec onds

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A

Explanation:

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Use the diagram to explain how convection occurs inside the earth. What could convection cause to occur on earths surface
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mantle convection is the very slow creeping motion of earths solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface.

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24. A 27-kg ball is tied to one end of a massless string of length 1.3 m. The other end of the string is tied to a nail in the c
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An aseroid with a mass of 8.4x10^8 kg and a planet with a mass of 6.2x10^23 kg come close to each other by a distance of 8x10^5
N76 [4]

So, the force of gravity that the asteroid and the planet have on each other approximately

\boxed{\sf{5.43 \times 10^{10} \: N}}

<h3>Introduction</h3>

Hi ! Now, I will help to discuss about the gravitational force between two objects. We already know that <u>gravitational force occurs when two or more objects interact with each other at a certain distance and generally orbit each other to their center of mass</u>. For the gravitational force between two objects, it can be calculated using the following formula :

\boxed{\sf{\bold{F = G \times \frac{m_1 \times m_2}{r^2}}}}

With the following condition :

  • F = gravitational force (N)
  • G = gravity constant ≈ \sf{6.67 \times 10^{-11}} N.m²/kg²
  • \sf{m_1} = mass of the first object (kg)
  • \sf{m_2} = mass of the second object (kg)
  • r = distance between two objects (m)

<h3>Problem Solving</h3>

We know that :

  • G = gravity constant ≈ \sf{6.67 \times 10^{-11}} N.m²/kg²
  • \sf{m_1} = mass of the first object = \sf{8.4 \times 10^8} kg.
  • \sf{m_2} = mass of the second object = \sf{6.2 \times 10^{23}} kg.
  • r = distance between two objects = \sf{8 \times 10^5}

What was asked :

  • F = gravitational force = ... N

Step by step :

\sf{F = G \times \frac{m_1 \times m_2}{r^2}}

\sf{F = 6.67 \times 10^{-11} \times \frac{8.4 \cdot 10^8 \times 6.2 \cdot 10^{23}}{(8 \times 10^5)^2}}

\sf{F = \frac{347.374 \times 10^{-11 + 8 + 23}}{64 \times 10^10}}

\sf{F \approx  5.43 \times 10^{20 - 10}}

\boxed{\sf{F \approx 5.43 \times 10^{10} \: N}}

<h3>Conclusion</h3>

So, the force of gravity that the asteroid and the planet have on each other approximately

\boxed{\sf{5.43 \times 10^{10} \: N}}

<h3>See More</h3>

Gravity is a thing has depends on ... brainly.com/question/26485200

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2 years ago
Place the following structures in the appropriate category based on their location in a cell
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Answer:

Cell surface.

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Nucleus

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Cytoplasm

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