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IgorLugansk [536]
4 years ago
6

10.For the following questions, use a periodic table and your atomic calculations to find the unknown information about each iso

tope:
You have an neutrally charged isotope with a mass number of 99 and an atomic number of 43. How many neutrons?

43
99
56
142
Physics
2 answers:
storchak [24]4 years ago
6 0
Okay this might be the hardest one of all um I think it is 99
Xelga [282]4 years ago
4 0

According to Articunojaz, the answer is 99.

Go ahead and give him brainliest now :D (a year l8r)

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PLEASE HELP I HAVE NO IDEA HOW TO COMPLETE THIS AND ITS DUE TONIGHT
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Answer:

Lo tienes que hacer con una tabla dde conversiones :)

Explanation:

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3 years ago
A sled of mass m is coasting on the icy surface of a frozen river. While it is passing under a bridge, a package of equal mass m
sweet [91]

Answer:B

Explanation:

Given

mass of Sled is m

another package of mass m is thrown on it

Suppose u be the initial velocity of sled

conserving momentum

mu=2mv

v=\frac{u}{2}

where v is the final velocity

Initial kinetic energy =\frac{1}{2}mu^2

Final Kinetic Energy=\frac{1}{2}(2m)\cdot (\frac{u}{2})^2

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5 0
3 years ago
How do I find magnitude of acceleration?
Leno4ka [110]
Divide the change in speed by the time for the change.
6 0
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Describe three physical changes that occur in nature?
Alex Ar [27]

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Explanation:

8 0
3 years ago
Read 2 more answers
a projectile whose masss is 10g is fired directly upward from ground level with an initial velocity of 1000m/s neglecting the ef
sammy [17]

Answer:

<em>The speed of the projectile when it impacts the ground is 1000 m/s</em>

Explanation:

<u>Vertical Launch</u>

When an object is launched vertically and upwards it starts to move at an initial speed vo, then the acceleration of gravity makes that speed to reduce until it reaches 0. The object has reached its maximum height. Then, it starts to move downwards in free fall, with initial speed zero and gradually increasing it until it reaches the ground level. We will demonstrate that the speed it has when impacts the ground is the same (and opposite) as the initial speed vo.

The speed when the object is moving upwards is given by

v_f=v_o-g.t

The time it takes to reach the maximum height is when vf=0, i.e.

0=v_o-g.t

solving for t

\displaystyle t=\frac{v_o}{g}

The maximum height reached is

\displaystyle y=\frac{gt^2}{2}=\frac{v_o^2}{2g}

Then, the object starts to fall. The object's height is given by

\displaystyle y=\frac{v_o^2}{2g}-\frac{gt'^2}{2}

where t' is the time the object has traveled downwards. The height will be 0 again when

\displaystyle \frac{v_o^2}{2g}=\frac{gt'^2}{2}

Solving for t'

\displaystyle t'=\frac{v_o}{g}

We can see the time it takes to reach the maximum height is the same it takes to return to ground level. Of course, the speed when it happens is

v_f=g.t'=v_o

Thus, the speed of the projectile when it impacts the ground is 1000 m/s

4 0
4 years ago
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