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EleoNora [17]
2 years ago
8

At the moment a hot cake is put in a cooler, the difference between the cakes and the cooler's

Physics
2 answers:
hram777 [196]2 years ago
5 0

Answer: D(t)= 50(4/5)^t

Explanation: If 1/5 of the temperature difference is lost each minute, that means 4/5 of the difference remains each minute. So each minute, the temperature difference is multiplied by a factor of 4/5 (or 0.8).

If we start with the initial temperature difference, 50° Celsius, and keep multiplying by 4/5, this function gives us the temperature difference t minutes after the cake was put in the cooler.

Ira Lisetskai [31]2 years ago
3 0

Answer:

D(t)=50 (0.8)^t

Explanation:

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The velocity of a projectile at launch has a horizontal component vh and a vertical component vv. When the projectile is at the
Usimov [2.4K]

Answer:

- horizontal component of the velocity: v_h (because it is constant)

- vertical component of the velocity: 0

- vertical component of the acceleration: -g=-9.8 m/s^2 (downward)

Explanation:

The motion of a projectile consists of two independent motions:

- Along the horizontal direction, there are no forces acting on the projectile (if we neglect air resistance), therefore the horizontal acceleration is zero and the horizontal component of the velocity, vh, is constant

- Along the vertical direction, there is only one force acting on the projectile: the force of gravity, downward, which produces a constant downward acceleration of g=9.8 m/s^2. As a consequence, the vertical component of the velocity changes according to

v_v(t) = v_v-gt

where vv is the initial vertical velocity and t the time. According to this equation, the vertical component of the velocity decreases first, then becomes zero at the point of maximum height, then becomes negative (= changes direction and points downward)

So, in summary, at the highest point of the trajectory we have:

- horizontal component of the velocity: v_h (because it is constant)

- vertical component of the velocity: 0

- vertical component of the acceleration: -g=-9.8 m/s^2 (downward)

3 0
3 years ago
Need help ???? Only answer if you think you know it
charle [14.2K]

Answer:

I believe it would be Direction B

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3 years ago
The metal with the highest melting temperature is tungsten which melts at around 3400 K. What is the wavelength of the peak of t
alekssr [168]

Explanation:

It is given that, the metal with the highest melting temperature is tungsten which melts at around 3400 K, T = 3400 K

We need to find the wavelength of the peak of the black body distribution for this temperature. It can be calculated using Wein's displacement law as :

\lambda\times T=k

k is the constant, k=2.89\times 10^{-3}\ m.k

\lambda=\dfrac{k}{T}

\lambda=\dfrac{2.89\times 10^{-3}\ m.k}{3400\ k}

\lambda=8.5\times 10^{-7}\ m

or

\lambda=850\ nm

The wavelength of infrared is from 700 nm to 1 mm. So, the lies in infrared region of the spectrum. Hence, this is the required solution.

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6 0
3 years ago
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