Question

At the moment a hot cake is put in a cooler, the difference between the cakes and the cooler's

Answer 1

Answer: D(t)= 50(4/5)^t

Explanation: If 1/5 of the temperature difference is lost each minute, that means 4/5 of the difference remains each minute. So each minute, the temperature difference is multiplied by a factor of 4/5 (or 0.8).

If we start with the initial temperature difference, 50° Celsius, and keep multiplying by 4/5, this function gives us the temperature difference t minutes after the cake was put in the cooler.

Answer 2

Answer:

D(t)=50 (0.8)^t

Explanation: