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EleoNora [17]
3 years ago
8

At the moment a hot cake is put in a cooler, the difference between the cakes and the cooler's

Physics
2 answers:
hram777 [196]3 years ago
5 0

Answer: D(t)= 50(4/5)^t

Explanation: If 1/5 of the temperature difference is lost each minute, that means 4/5 of the difference remains each minute. So each minute, the temperature difference is multiplied by a factor of 4/5 (or 0.8).

If we start with the initial temperature difference, 50° Celsius, and keep multiplying by 4/5, this function gives us the temperature difference t minutes after the cake was put in the cooler.

Ira Lisetskai [31]3 years ago
3 0

Answer:

D(t)=50 (0.8)^t

Explanation:

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Imagine a landing craft approaching the surface of Callisto, one of Jupiter's moons. If the engine provides an upward force (thr
nordsb [41]

Answer:

W=3456 N

Explanation:

Force 1 F_1=3456

Force 2 F_2=2333N

Acceleration at stage 2 a_2=0.39

Generally the weight of the Craft W is given as

W= upward force(thrust)

Therefore

W=3456 N

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Radar is used to determine distances to various objects by measuring the round-trip time for an echo from the object. (a) How fa
BartSMP [9]

Answer

given,

Echo time = t = 1000 s

speed = ?

v = \dfrac{d}{t}

a) speed of electromagnetic wave

c = \dfrac{d}{t}

wave travels Venus two time

c = \dfrac{2d}{t}

d = \dfrac{ct}{2}

d = \dfrac{3 \times 10^8\times 1000}{2}

d = 1.5 x 10¹¹ m

b) now, echo time

    c = \dfrac{2d}{t}

    t = \dfrac{2d}{c}

    t = \dfrac{2\times 75}{3 \times 10^8}

          t = 5 x 10⁻⁷ s

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Which of these objects would need the largest force to create an acceleration of 1 m/s2?
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Por favor, necesito ayuda urgente 4. vectores perpendiculares de 25 y 40 unidades cada uno. Hallar gráfica y numericamente el ve
Darina [25.2K]

Answer:

4)  R = 47.17 units , 5)  R= 10,29 unidades, 6)   R= 2994,4 km ,    θ = -33,7

Explanation:

Este es un ejercicio de adición de vectores

4) como los vectores son perpendiculares.

Para encontrar la resultante podemos usar el teorema de pitoras

        R =  √ a² + b²

        R = √√ ( 25² + 40²)

        R =  47,17 unidades

5)  Este caso como el angulo es diferente de 90 debemos usar la relación de pitoras completa

        R² =  a² + b² + 2 a b cos θ

donde el angulo es entre los vectores a y b

        R² = 12² + 16² – 2 12 16 cos 40

        R²= 400 – 294,16

       R= 10,29 unidades

6) En este caso los dos desplazamientos son perpendiculares, por lo cual Usamos el teorema de Pitágoras

          R = √ (2400² + 1600²)

          R= 2994,4 km

para el angulo de este desplazamiento usamos trigonometría

           tan θ = y/x

           θ = tan⁻¹ y/x

           θ = tan⁻¹ 1600/(-2400)

           θ = -33,7  

TRASLATE

This is a vector addition exercise

4) as the vectors are perpendicular.

To find the result we can use the Poreor theorem

        R = √ a² + b²

        R = √ (25² + 40²)

        R = 47.17 units

5) This case, as the angle is different from 90, we must use the complete ratio of the pitoras

        R² = a² + b² + 2 a b cos θ

where the angle is between vectors a and b

        R² = 12² + 16² - 2 12 16 cos 40

         R² = 400 - 294.16

       R = 10.29 units

6) In this case the two displacements are perpendicular, which is why we use the Pythagorean theorem

          R = √ (2400² + 1600²)

          R = 2,994.4 km

for the angle of this displacement we use trigonometry

           tan θ = y / x

           θ = tan⁻¹ y / x

           θ = tan⁻¹ 1600 / (- 2400)

           θ = -33.7

3 0
3 years ago
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