Answer:
Step-by-step explanation:
The given relation between length and width can be used to write an expression for area. The equation setting that equal to the given area can be solved to find the shed dimensions.
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<h3>Given relation</h3>
Let x represent the width of the shed. Then the length is (2x+3), and the area is ...
A = LW
20 = (2x+3)(x) . . . . . area of the shed
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<h3>Solution</h3>
Completing the square gives ...
2x² +3x +1.125 = 21.125 . . . . . . add 2(9/16) to both sides
2(x +0.75)² = 21.125 . . . . . . . write as a square
x +0.75 = √10.5625 . . . . . divide by 2, take the square root
x = -0.75 +3.25 = 2.50 . . . . . subtract 0.75, keep the positive solution
The width of the shed is 2.5 feet; the length is 2(2.5)+3 = 8 feet.
Let m the tens digit and n the ones
the Original number is 10m+n
7(m+n) =10m+n
7m+7n=10m+n
6n=3m
Reversing the number 10n+m
10n+m=18+n+m
9n=18
n=2
6n=3m
6(2)=3m
3m=12
m=4
the number is 10m+n=10(4)+2=42
Answer: Use the slope formula to find the slope
m = −2−b/2
X^3 * x^2 - 4 is your answer. Hope this helps!
Answer:
588 in³
Step-by-step explanation:
Break it up in three parts.
Left part: 7*8*3 = 168
Mid part: 6*6*7 = 252
Right part: 7*8*3 = 168
Sum: 168+252+168 = 588
