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alekssr [168]
3 years ago
15

Predict what will happen to the ammonia equilibrium system if hydrogen gas (H2) is added in the following reaction. N2(g) + 3H2(

g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. 2NH3(g The equilibrium shifts to the left.
The reaction reaches completion.
The equilibrium remains the same.
The equilibrium shifts to the right.
Chemistry
2 answers:
Vedmedyk [2.9K]3 years ago
8 0
Correct answer is option C i.e. <span>The equilibrium shifts to the right.

Reason:
Following reaction is involved in present case:
N2 (g)     +         3H2 (g)       </span>⇄<span>     2NH3(g)     

Now, according to </span><span>Le Chatelier's  principle, if pressure is increased/decreased in system, the reaction equilibrium will move in direction to minimize this effect.  So, if H2 is added in reaction system, it will increase pressure of reaction system. Hence, equilibrium will shift towards right, so as to minimize the effect of increasing pressure.  </span>
natulia [17]3 years ago
7 0
The equilibrium shifts to the right
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Boron sulfide, B2S3(s), reacts violently with water to form dissolved boric acid (H3BO3) and hydrogen sulfide gas.Express your a
ioda

Answer:

Explanation:

From the statement of the problem,

  B₂S₃_{s} + H₂O_{l}  →  H₃BO₃_{aq} + H₂S_{g}

              B₂S₃ + H₂O  →  H₃BO₃ + H₂S

We that the above expression does not conform with the law of conservation of mass:

To obey the law, we need to derive a balanced reaction equation:

   Let us use the mathematical method to obtain a balanced equation.

let the balanced equation be:

                        aB₂S₃ + bH₂O  →  cH₃BO₃ + dH₂S

where a, b, c and d will make the equation balanced.

  Conservating B: 2a = c

                          S: 3a = d

                          H: 2b = 3c + 2d

                           O: b = 3c

   if a = 1,

      c = 2,

      b = 6,

      2d = 2(6) - 3(2) = 6, d = 3

Now we can input this into our equation:

                     B₂S₃ + 6H₂O  →  2H₃BO₃ + 3H₂S

    B₂S₃_{s} + 6H₂O_{l}  →  2H₃BO₃_{aq} + 3H₂S_{g}

4 0
3 years ago
1.For the reaction P4 O10(s) + 6H2O(l) → 4H3PO4(aq), what mass of P
Alex17521 [72]
P₄O₁₀ + 6H₂O → 4H₃PO₄
The equation shows us that the molar ratio of
P₄O₁₀ : 6H₂O = 1:6

We also know that one mole of a substance contains 6.02 x 10²³ particles. We can use this to calculate the moles of water.
moles(H₂O) = (5.51 x 10²³) / (6.02 x 10²³)
= 0.92 mole
That means moles of P₄O₁₀ = 0.92 / 6
= 0.15

Each mole of P₄O₁₀ contains 4 moles of P. 
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Mr of P = 207 grams per mol
Mass of P = 207 x 0.6
= 124.2 grams
5 0
3 years ago
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