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2 years ago

There are 70 fisherman and 5 sea bass in the lake. Are sea bass considered a limiting factor?

Chemistry

1 answer:

Olin [163]2 years ago

8 0

Answer:

yes

Explanation:

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State the relationship between electron configuration and location of an element in the period table

inn [45]

Answer:

elements in same group have same valence electron.

period of element is equal to valence shell

Explanation:

if the elements are in a same group then they will be having same number of valence electron.

the period of an element in periodic table is equal to the valence shell of the element. that is if the valence electron are in 3 rd shell then the element will be in third period.

5 0

3 years ago

Magma that is rich in feldspar and silica is called?

weeeeeb [17]

Answer:

<h3>magma that is rich in feldspar and silica is called STRATOVOLCANO.</h3>

3 0

3 years ago

1. How many moles of oxygen gas are needed to form 21.8 liters of water vapor?

BaLLatris [955]

0.781 moles

Explanation:

We begin by balancing the chemical equation;

O₂ (g) + 2H₂ (g) → 2H₂O (g)

21.8 Liters = 21.8 Kgs

To find how many moles are in 28.1 Kg H₂O;

Molar mass of H₂O = 18 g/mol

28.1/18

= 1.56 moles

The mole ratio between water vapor and oxygen is;

1 : 2

x : 1.56

2x = 1.56

x = 1.56 / 2

x = 0.781

0.781 moles

7 0

3 years ago

How many mol of hydrogen are needed to double the volume occupied by 0.34 mol of hydrogen,

natima [27]

Answer:

0.68

Explanation:

Number of moles is directly propotionalto the volume at standard condition.

6 0

3 years ago

For each of the esters provided, identify the alcohol and the carboxylic acid that reacted.

Veronika [31]

Answer:

52. The alcohol USED => methanol, CH3OH

The carboxylic acid USED => propanoic acid, CH3CH2COOH.

53. The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

Explanation:

52. To obtain Methyl propanoate, CH3CH2COOCH3, we simply react propanoic, CH3CH2COOH and methanol, CH3OH together as shown below:

CH3CH2COOH + CH3OH —> CH3CH2COOCH3 + H2O

The alcohol used: methanol, CH3OH

The carboxylic acid used: propanoic acid, CH3CH2COOH.

53. To obtain Ethyl methanoate, HCOOCH2CH3, we simply react

Formic acid, HCOOH and ethanol, CH3CH2OH together as show below:

HCOOH + CH3CH2OH —> HCOOCH2CH3 + H2O

The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

7 0

3 years ago