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almond37 [142]
2 years ago
15

There are 70 fisherman and 5 sea bass in the lake. Are sea bass considered a limiting factor?

Chemistry
1 answer:
Olin [163]2 years ago
8 0

Answer:

yes

Explanation:

You might be interested in
A LA TEMPERATURA DE 35°C, UNA MUESTRA DE DIOXIDO DE CARBONO OCUPA UN VOLUMEN DE 350 ML. ¿Qué CAMBIO DE VOLUMEN SE PRODUCIRA SI L
Kisachek [45]

Answer:

New volume = 150 mL

Explanation:

Initial temperature, T₁ = 35°C

Initial volume, V₁ = 350 mL

We need to find the change in volume when the temperature drops to 15°C.

The relation between the temperature and the volume is given by Charle's law. Let new volume is V₂. It can be given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{350\times 15}{35}\\\\V_2=150\ mL

So, the new volume is 150 mL.

8 0
3 years ago
If you want 2 miles of Silver (Ag) from the reaction below, how many grams of copper should you start with? Reaction: Cu + 2AgNO
RSB [31]

Answer:

You should start with 63.54 grams of copper.

Explanation:

The chemical reactions are processes in which the nature of the substances changes, that is, from some initial substances called reactants, totally different ones called products are obtained.

In the chemical reaction, the formulas of reagents and products appear preceded by numbers (the stoichiometric coefficients) that indicate the proportions according to which the transformation occurs. So you can say that stoichiometry establishes relationships between the molecules or elements that make up the reactants of a chemical equation with the products of said reaction. The relationships that are established are MOLAR relationships between the compounds or elements that make up the chemical equation: always in MOLES.

The stoichiometric coefficients of a chemical equation are due to the fact that the atoms present before the reaction must be the same after the reaction, although they will have been rearranged to produce new substances.

If you want 2 moles of silver (Ag), for stoichiometry of the reaction you need a moles of copper Cu. Being the molar mass of copper Cu 63.54 g / mole, then:

1 mole*63.54 g/mole= 63.54 g

<u><em> You should start with 63.54 grams of copper.</em></u>

<u><em></em></u>

8 0
3 years ago
An alloy is made up of more than one type of what?
pychu [463]
More than one type of metallic elements.
4 0
3 years ago
If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?
ICE Princess25 [194]

<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.

<u>Explanation:</u>

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}

where,

k = rate constant = ?

t = time taken = 1.52 hrs

[A_o] = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}

To calculate the half life period of first order reaction, we use the equation:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life period of first order reaction = ?

k = rate constant = 0.2098hr^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0
3 years ago
Cacl2+na3po4 ca3po42 + nacl
Alex787 [66]
<h3>Answer:</h3>

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

<h3>Explanation:</h3>

We are given the Equation;

CaCl₂ + Na₃PO₄→ Ca₃(PO₄)₂ + NaCl

Assuming the question requires us to balance the equation;

  • A balanced chemical equation is one that has equal number of atoms of each element on both sides of the equation.
  • Balancing chemical equations ensures that they obey the law of conservation of mass in chemical equations.
  • According to the law of conservation of mass in chemical equation, the mass of the reactants should always be equal to the mass of the products.
  • Balancing chemical equations involves putting appropriate coefficients on the reactants and products.

In this case;

  • To balance the equation we are going to put the coefficients 3, 2, 1, and 6.
  • Therefore; the balanced equation will be;

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

5 0
3 years ago
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