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almond37 [142]
3 years ago
15

There are 70 fisherman and 5 sea bass in the lake. Are sea bass considered a limiting factor?

Chemistry
1 answer:
Olin [163]3 years ago
8 0

Answer:

yes

Explanation:

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During translation, the new polypeptides are often directed to specific parts of the cell by the presence or absence of short se
kotegsom [21]

Answer:

The correct option is b. an amino-terminal signal

Explanation:

A polypeptide that will eventually fold to become an ion channel protein, it means a kind of integral membrane protein, has an amino terminal signal that indicates its delivery to endoplasmic reticulum (ER) and then to the membrane. This type of signal usually consist in a nucleus of 6 to 12 aminoacids and one or more basic aminoacids. Once the polypeptide enters the ER, this signal is removed.

6 0
3 years ago
What elements make up duralumin( an alloy)?​
Bogdan [553]

Answer:

In addition to aluminium, the main materials in duralumin are copper, manganese and magnesium.

4 0
3 years ago
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How can Newton's Third Law of Motion be used to explain why it is difficult to walk on a slippery surface, such as ice?
Olenka [21]
E ground pushes you forward. But that interaction is friction. Reduce friction and it doesn't matter how strong your legs are, the surface is incapable of pushing you accordingly. The coefficient of static friction is very low so it is easy to slide your foot rather than push.
6 0
3 years ago
An someone help me with this
valina [46]

2)c

3)b

4)c

5)a

hope this helps!!!

6)a

7)c

3 0
3 years ago
Read 2 more answers
Each student in a class placed a 2.00 g sample of a mixture of Cu and Al in a beaker and placed the beaker in a fume hood. The s
Aleks [24]

Answer:

Percentage mass of copper in the sample = 32%

Explanation:

Equation of the reaction producing Cu(NO₃) is given below:

Cu(s)+ 4HNO₃(aq) ---> Cu(NO₃)(aq) + 2NO₂(g) + 2H₂O(l)

From the equation of reaction, 1 mole of Cu(NO₃) is produced from 1 mole of copper. Therefore, 0.010 moles of Cu(NO₃) will be produced from 0.010 mole of copper.

Molar mass of copper = 64 g/mol

mass of copper = number of moles * molar mass

mass of copper = 0.01 mol * 64 g/mol = 0.64 g

Percentage by mass of copper in the 2.00 g sample = (0.64/2.00) * 100%

Percentage mass of copper in the sample = 32%

3 0
3 years ago
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