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miss Akunina [59]
3 years ago
11

HELP: MODELING MOLECULES!!!!!!!!!!!!!!!!

Chemistry
1 answer:
garik1379 [7]3 years ago
8 0
<span>Sulfur Hexachloride SCl6 So now we count the number of valence electrons each has by seeing what column it's in, (1-8) not counting the columns of the transition metals. Since Sulfur is in the 6th and Chlorine is in the 7th, and there are 6 chlorines, we can add up all their valence electrons: 6*1+7*6=48 valence electrons. But remember that electrons come in pairs, either in bonds or as lone pairs. So I usually divide the valence electron number by 2 and just think about placing pairs. It's up to you, but I think it's convenient since we can count "1" in our mind each time we place a bond or a electron pair. So we need to place 24 pairs/bonds. So we can guess that sulfur is a central atom and draw out a bond from sulfur to each chlorine. Since Sulfur is in the 3rd row it can use d-orbitals to break the octet rule. So when we bond all the chlorines onto sulfur we get:
(see the figure)

and 
</span><span>So we made 6 bonds, that means we used up 12 electrons, so if you're counting (AND YOU SHOULD BE!) you have 36 electrons or simply 18 electron pairs left to place. Now let's give chlorine a neutral charge.</span>

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Chromic acid (H2CrO4) is an acid that is used in ceramic glazes and colored glass. The pH of a 0.078 M solution of chromic acid
cestrela7 [59]

Answer:

Ka = 0.1815

Explanation:

Chromic acid

pH = ?

Concentration = 0.078 M

Ka = ?

HCl

conc. = 0.059M

pH = -log(H+)

pH = -log(0.059) = 1.23

pH of chromic acid = 1.23

Step 1 - Set up Initial, Change, Equilibrium table;

H2CrO4 ⇄  H+   +   HCrO4−

Initial - 0.078M 0   0

Change : -x    +x       +x

Equilibrium : 0.078-x    x      x

Step 2- Write Ka as Ratio of Conjugate Base to Acid

The dissociation constant Ka is [H+] [HCrO4−] / [H2CrO4].

Step 3 - Plug in Values from the Table

Ka = x * x / 0.078-x

Step 4 - Note that x is Related to pH and Calculate Ka

[H+] = 10^-pH.

Since x = [H+] and you know the pH of the solution,

you can write x = 10^-1.23.

It is now possible to find a numerical value for Ka.

Ka =  (10^-1.23))^2 / (0.078 - 10^-1.23) = 0.00347 / 0.0191156

Ka = 0.1815

4 0
3 years ago
The molecular mass of the compound is 132 amu. What is the molecular formula?
densk [106]
C6H12O3 is a molecular formula that contains 54.5% C, 9.1% H, and 36.4% O and <span>has a molar mass 132 amu. </span>
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what additional detail supports the point on view in the chart? 1-it doesn’t make sense to have an “honor system.” 2-someone sho
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Answer:

I wanna say 3

Explanation:

Provincetown is known for them so getting rid of them would be a bad thing.

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What is sewageband dirty amd water​
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Answer:

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The equilibrium constant Kc for the reaction below is 0.00584 at a certain temperature. Br2(g) ⇌ 2Br(g) If the initial concentra
Vinil7 [7]

Answer:

Explanation:

Given that:

The chemical equation for the reaction is:

             Br2(g)    ⇌  2Br(g)

Initially  0.0345M  0.0416M

Q_C = \dfrac{[Br]^2}{[Br_2]} = \dfrac{(0.0416)^2}{(0.0345)}= 0.05016

Q_C =0.05016 >>> K_c(0.00584)

Thus, the given reaction will proceed in the  backward direction

 The I.C.E table is as follows:

                       Br2(g)    ⇌  2Br(g)

I               0.0345                 0.0416

C                 +x                        -2x

E             (0.0345+x)            (0.0416 -2x)

K_c = \dfrac{[Br]^2}{[Br_2]} = \dfrac{(0.0416-2x)^2}{(0.0345+x)} = 0.00584

= 0.00173056 - 0.0832x - 0.0832x + 4x² = 0.00584 (0.0345 +x)

= 0.00173056 - 0.166x + 4x² = 2.0148× 10⁻⁴ + 0.00584x

= 0.00173056 - 2.0148× 10⁻⁴ - 0.166x - 0.00584x + 4x²

= 0.00152908  - 0.17184x + 4x²

Solving by using Quadratic formula

x = 0.03038 or 0.0126

For x = 0.03038

At equilibrium

[Br₂] = (0.0345 + 0.03038) = 0.06488 M

[Br] =  (0.0416 -2(0.03038)) = - 0.01916 M

Since we have a negative value for [Br], we discard the value for x

For x = 0.0126

At equilibrium

[Br₂] = (0.0345 + 0.0126) = 0.0471 M

[Br] =  (0.0416 -2(0.0126)) = 0.0164 M

4 0
3 years ago
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