3 years ago

Solve in C: (3+2i)z+1-2i=2iz-2+i

1 answer:

5 0

Hello,
(3+2i)z+1-2i=2iz-2+i
<==>(3+2i-2i)z=-2+i-1+2i
<==>3z=3(-1+i)
<==>z=-1+i

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Step-by-step explanation:

We need to evaluate $10^2 + 6 \,\,multiplied\,\, by\,\, 7 + 8$

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$10^2 + 6 \,\,multiplied\,\, by\,\, 7 + 8\\=(10^2+6)\times(7+8)\\=(100+6)\times(15)\\=106\times15\\=1590$

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