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Drupady [299]
4 years ago
9

Can someone please help me ASAP

Chemistry
1 answer:
Natalka [10]4 years ago
4 0
The answer is D. Primary
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A 37.2-g sample of lead (Pb) pellets at 20°C is mixed with a 62.7-g sample of lead pellets at the same temperature. What are th
Vesnalui [34]

Answer:

Mass of sample is 99.9 g, density of ample is 11.35 g/cm^{3} and temperature of sample is 20^{0}\textrm{C}

Explanation:

Mass is an additive property. Therefore mass of combined sample is summation of masses of two pellets.

Mass of combined sample = (37.2+62.7) g = 99.9 g

Density is an intensive property. Therefore density of combined sample of lead will be same as with density of Pb.

Density of combined sample = 11.35 g/cm^{3}

Temperature is an intensive property. Therefore temperature of combined sample of lead will be same as with individual pellets.

temperature of combined sample = 20^{0}\textrm{C}

8 0
3 years ago
You drop a rock weighing 23.2 g into a graduated cylinder that contains 55 mL. The level
snow_lady [41]

Answer:

<h2>3.31 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 23.2 g

volume = final volume of water - initial volume of water

volume = 62 - 55 = 7 mL

We have

density =  \frac{23.2}{7}  \\  = 3.314285

We have the final answer as

<h3>3.31 g/mL</h3>

Hope this helps you

8 0
3 years ago
Almost 98% of earthquakes occur at the boundary of a tectonic plates when they slide against one another. Despite this, Indiana
oksian1 [2.3K]

the only explanation would be that it is on top of a hotspot I don't know if this helps at all

8 0
3 years ago
Suppose that coal of density 1.5 g/cm^3 is pure carbon. (It is, in fact, much more complicated, but this is a reasonable first a
NISA [10]

Answer:

q = -6464.9 kJ

Explanation:

We are given that the heat of combustion is  ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.

vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³

m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g

mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol

q =  −394 kJ /mol C x 16.41 mol C = -6464.9 kJ

7 0
3 years ago
What is the concentration (in ppm) of Mn7+ in a 0.00300 M KMnO4 solution?  Note:  for dilute aqueous solutions, 1 ppm = 1 mg/L.
aleksklad [387]

We know that there is 1 mole of Mn for every 1 mole of KMnO4, therefore the molarity of Mn is similar with KMnO4:

Mn = 0.00300 M

Molar mass of Mn is 54.94 g / mol. Molarity (M) is moles / L, therefore:

Mn = (0.00300 moles / L) * (54.94 g / mol) * (1000 mg / g)

<span>Mn = 164.82 mg / L = 164.82 ppm</span>

3 0
3 years ago
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