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sergey [27]
2 years ago
14

Given the following reaction:

Chemistry
1 answer:
fredd [130]2 years ago
7 0

Answer:D. In order to restore equilibrium, the reaction shifts right, towards products

Explanation:

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3 years ago
Find the weight of HNO_3 present in 20ml, 0.30 N
yanalaym [24]

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mass of HNO₃ = 0.378 g

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Normality = Molarity * number of equivalents

Molarity = Normality/number of equivalents

normality of HNO₃ = 0.30 N, Volume = 20 mL

HNO₃ ionizes in the following way:

HNO₃(aq) ----> H⁺ + NO₃⁻

Therefore, number of equivalents for HNO₃ is 1

molarity of HNO₃ = 0.30/1 =0.30 mol/dm³

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Number of moles of HNO₃ = 0.30 mol/dm³ * 20ml * 1 dm³ /1000 mL

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