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Marianna [84]
3 years ago
14

The parents of a young child carefully placed plastic plug protectors in all the electrical outlets in their house. Which statem

ent best describes the role of the plastic protectors? (2 points)
A)Electricity is transported through wires, which are good conductors of electricity. To prevent the flow of electricity into other objects, a material that will prevent the flow of electricity from escaping the wires needs to be used. Certain types of plastics, which are good conductors, are one of many materials that can be used.
B)Electrical outlets contain metal wires that are good conductors of electricity. In order to promote electrical safety, the parents covered the outlets with plastic, an insulator that prevents electrical current from flowing to another object.
C)Plastic is a good conductor of electricity. Placing plastic covers over the electrical outlets allows the electrical current to be redirected back to the plug and ensures the safety of those around the outlets.
D)Plastics and metals are good conductors. This is why plastics can be used to prevent the flow of electricity from materials, like metal wires, to other objects. By preventing the flow of electricity, these help keep people safe.
Chemistry
2 answers:
crimeas [40]3 years ago
7 0

The answer is B) Electrical outlets contain metal wires that are good conductors of electricity. In order to promote electrical safety, the parents covered the outlets with plastic, an insulator that prevents electrical current from flowing to another object.

GREYUIT [131]3 years ago
5 0

The answer is B)Electrical outlets contain metal wires that are good conductors of electricity. In order to promote electrical safety, the parents covered the outlets with plastic, an insulator that prevents electrical current from flowing to another object.

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Below are the structures of three fatty acids, palmitic acid, stearic acid, and oleic acid. what combination of these fatty acid
irina1246 [14]
I think the fatty acids that may be used to make a fat that is liquid at room temperature are One plamitic acid, one stearic acid, and one oleic acid.
Fatty acids are composed of linked chains of carbon atoms with an organic acid group at the end of the chain. Liquid fats or Oils are mainly obtained from plants or fish sources, and have high percentages of unsaturated fatty acids.

7 0
3 years ago
Read 2 more answers
Calculate the number of grams of CO that can react with 0.400 kg of Fe2O3.
aleksandr82 [10.1K]

Answer:

mass of CO = 210.42 g

mass in three significant figures = 210. g

Explanation:

Given data:

mass of Fe2O3 = 0.400 Kg

mass of CO= ?

Solution:

chemical equation:

Fe2O3 + 3CO → 2Fe + 3CO2

Now we will calculate the molar mass of  Fe2O3 and CO.

Molar mass of  Fe2O3 = (55.845 × 2) + (16 × 3) = 159.69 g/mol

Molar mass of CO = 12+ 16 = 28 g/mol

now we will convert the kg of Fe2O3 in g.

mass of Fe2O3 = 0.400 kg × 1000 = 400 g

number of moles of Fe2O3  = 400 g/ 159.69 g/mol = 2.505 mol

mass of CO = moles of Fe2O3 × 3( molar mass of CO)

mass of CO = 2.505 mol × 84 g/mol

mass of CO = 210.42 g

mass in three significant figures = 210. g

5 0
3 years ago
Read 2 more answers
How do elements on the right side of the periodic table differ from elements on the left side of the table?
lozanna [386]

The answer is c.


Elements on the left side of the table are metals, such as sodium, lithium, potassium, etc.


Elements on the right side are non metals, such as Chlorine, Fluorine, Bromine, etc.

4 0
3 years ago
In a science lab, a student heats up a chemical from 10 °C to 25 °C which requires thermal energy of 30000 J. If mass of the obj
olganol [36]

Answer:

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

Explanation:

Step 1: Data given

Initial temperature = 10.0 °C

Final temperature = 25.0 °C

Energy required = 30000 J

Mass of the object = 40.0 grams

Step 2: Calculate the specific heat capacity of the object

Q = m* c * ΔT

⇒With Q = the heat required = 30000 J

⇒with m = the mass of the object = 40.0 grams

⇒with c = the specific heat capacity of the object = TO BE DETERMINED

⇒with ΔT = The change in temperature = T2 - T2 = 25.0 °C - 10.0°C = 15.0 °C

30000 J = 40.0 g * c * 15.0 °C

c = 30000 J / (40.0 g * 15.0 °C)

c = 50 J/g°C

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

3 0
3 years ago
Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io
Lera25 [3.4K]

Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

3 0
3 years ago
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