Answer:
Total pressure = 56.77 bar
Explanation:
Given data:
Mass of dioxygen = 8 g
Mass of dihydrogen = 4 g
Volume of vessel = 1 dm³
Temperature = 27°C (27+273 = 300 K)
R = 0.083 bar.dm³ / mol.K
Total pressure = ?
Solution:
Number of moles of dioxygen:
Number of moles = mass/molar mass
Number of moles = 8 g/ 32 g/mol
Number of moles = 0.25 mol
Pressure of dioxygen:
PV = nRT
P = nRT/V
P = 0.25 mol × 0.083 bar.dm³ / mol.K × 300 K / 1 dm³
P = 6.97 bar.dm³ /1 dm³
P = 6.97 bar
Number of moles of dihydrogen:
Number of moles = mass/molar mass
Number of moles = 4 g/ 2 g/mol
Number of moles = 2 mol
Pressure of dihydrogen:
PV = nRT
P = nRT/V
P = 2 mol × 0.083 bar.dm³ / mol.K × 300 K / 1 dm³
P = 49.8 bar.dm³ /1 dm³
P = 49.8 bar
Total pressure of mixture in a vessel:
Total pressure = P (O₂) + P(H₂)
Total pressure = 6.97 bar + 49.8 bar
Total pressure = 56.77 bar
