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lyudmila [28]
3 years ago
12

Assuming NORMAL conditions, select all of the following that would be found in lesser concentrations in the urine than in the gl

omerular filtrate.
a. glucose
b. amino acids
c. water
d. creatinine
e. hydrogen ions
f. urea
Chemistry
1 answer:
Setler79 [48]3 years ago
3 0
The answer is c if it’s wrong immm soo sorry.
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Answer: The molality of solution is 17.6 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n}{W_s}

where,

n = moles of solute

W_s = weight of solvent in kg

moles of acetone (solute) = 0.241

moles of water (solvent )= (1-0.241) = 0.759

mass of water (solvent )= moles\times {\text {Molar Mass}}=0.759\times 18=13.7g=0.0137kg

Now put all the given values in the formula of molality, we get

Molality=\frac{0.241}{0.0137kg}=17.6mole/kg

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