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3 years ago

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Assuming NORMAL conditions, select all of the following that would be found in lesser concentrations in the urine than in the gl

omerular filtrate.
a. glucose
b. amino acids
c. water
d. creatinine
e. hydrogen ions
f. urea

1 answer:

Setler79 [48]3 years ago

3 0

The answer is c if it’s wrong immm soo sorry.

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Please help me understand how to...

KonstantinChe [14]

Answer:

$m_{Cr_2O_3}^{actual}=62.4gCr_2O_3$

Explanation:

Hello!

In this case, according to the reaction:

$4Cr+3O_2\rightarrow 2Cr_2O_3$

We can see there is a 4:2 mole ratio between chromium and chromium (III) oxide, this, for the given 56.2 g of chromium, the theoretical yield of the oxide product is computed down below:

$m_{Cr_2O_3}^{theoretical}=56.2gCr*\frac{1molCr}{52.0gCr}*\frac{2molCr_2O_3}{4molCr} *\frac{151.99gCr_2O_3}{1molCr_2O_3} =82.13gCr_2O_3$

Now, considering the 76.0-% yield for this reaction, the actual yield turns out:

$m_{Cr_2O_3}^{actual}=82.13gCr_2O_3*\frac{76.0gCr_2O_3}{100gCr_2O_3} \\\\m_{Cr_2O_3}^{actual}=62.4gCr_2O_3$

Best regards!

3 0

3 years ago

What happens in a reduction?

MatroZZZ [7]

Answer:

A. An element gains one or more electrons

Explanation:

Reduction is a chemical reaction that involves the gaining of electrons by one of the atoms involved in the reaction between two chemicals. The term refers to the element that

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3 years ago

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A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling

Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

<u>Explanation:</u>

To calculate the molarity of solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L$

Hence, the concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

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3 years ago

3. A vapor is which state of matter? (1 point)<br> solid<br> liquid<br> gas<br> all of the above

lidiya [134]

Answer:

Gas.

Explanation:

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3 years ago

the sublevel that has the largest number of differently shaped orbitals is the f sublevel. True False

GrogVix [38]

The answer to this is true.

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3 years ago

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