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Reil [10]
3 years ago
13

Silver (ag) has a molar mass of 107.8682 g, nitrogen has a molar mass of 14.0067 g, and oxygen has a molar mass of 15.9994 g. wh

at is the molar mass of silver nitrate, agno3?
Chemistry
2 answers:
alina1380 [7]3 years ago
4 0

Answer : The molar mass of silver nitrate (AgNO_3) is, 169.87 g

Explanation :

Molar mass : It is defined as mass of 1 mole of a substance.

Given:

Molar mass of Sliver (Ag) = 107.8682 g

Molar mass of nitrogen (N) = 14.0067 g

Molar mass of oxygen (O) = 15.9994 g

Now we have to calculate the molar mass of silver nitrate (AgNO_3)

Molar mass of silver nitrate (AgNO_3) = Molar mass of Sliver (Ag) + Molar mass of nitrogen (N) + (3 × Molar mass of oxygen (O))

Molar mass of silver nitrate (AgNO_3) = 107.8682 g + 14.0067 g + 3(15.9994 g)

Molar mass of silver nitrate (AgNO_3) = 169.87 g

Therefore, the molar mass of silver nitrate (AgNO_3) is, 169.87 g

ASHA 777 [7]3 years ago
3 0
AgNO3=
(ag + n + o3) =  \\  (107.8682) + (14.0067) + (15.9994 \times 3) \\  = 169.8731g \: per \: mole
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calculate the molarity of MgCl2 in the following solution: 5.34 g of MgCl2 is dissolved and diluted to 214 mL of solution.
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<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

\quad\hookrightarrow\quad \sf {0.262M }

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ :</u></h3>

Molarity is used to measure the concentration of a solution , so it is also as molar concentration. It is denoted as M or Mol/L

<u>We </u><u>are </u><u>given </u><u>that </u><u>:</u>

  • Weight of \sf MgCl_{2} = 5.34g
  • Volume of solution = 214 ml , or 0.214 L

The molar mass of magnesium chloride ( \sf MgCl_{2} ) is 95.21 g / mol

We can calculate the molarity of the solution by dividing the number of moles of solute by volume of solvent in liter ,i.e:

\quad\longrightarrow\quad \sf  {M = \dfrac{n}{V} } ‎ㅤ‎ㅤ‎ㅤ⸻( 1 )

<em>Where,</em><em> </em>

  • M = molarity
  • n = number of moles
  • V = Volume

We can calculate the number of moles by dividing the actual mass by its molar mass ,i.e:

\quad\longrightarrow\quad \sf { n = \dfrac{w}{m}}‎ㅤ‎ㅤ‎ㅤ‎⸻ ( 2 )

<em>W</em><em>here,</em>

  • n = number of moles
  • m = molar mass
  • w = actual mass

<u>Therefore</u><u>,</u>

\implies\quad \tt {n =\dfrac{w}{m} }

\implies\quad \tt { n =\dfrac{5.35\: g}{95.21\: g /mol}}

\implies\quad{\pmb{ \tt {n = 0.056 mol}} }

<u>P</u><u>utting </u><u>the </u><u>values </u><u>in </u><u>equation </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u>

\implies\quad \tt {M=\dfrac{n}{V} }

\implies\quad \tt { M =\dfrac{0.056\:mol}{0.214\:L}}

\implies\quad\underline{\pmb{ \tt { M = 0.262 \:M }}}

7 0
2 years ago
Solids, liquids, and gases are the three most commonly accepted phases of matter. Explain the properties of each phase, includin
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