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quester [9]
3 years ago
9

What does a eukaryotic cell have that a prokaryotic cell theory?

Biology
2 answers:
jonny [76]3 years ago
7 0
Eukaryotic cells have<span> organelles, membrane-bound structures that perform different functions in the </span>cell<span>, and </span>prokaryotic cells do not<span>. Some typical </span>eukaryotic<span> organelles include the nucleus, mitochondria, ribosomes, Golgi apparati and chloroplasts.</span>
hram777 [196]3 years ago
6 0
Eukaryotic cells have a nucleus, prokaryotic cells don't.
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Species change over time through a process called evolution. is that a theory law or hypothesis?
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Bob, a nutritionist who works for the university medical center, has been asked to prepare special diets for two patients, susan
abruzzese [7]

Answer and Explanation:

Possibly, you forgot to attach the table with the contents of each food. Therefore, I calculated the task with similar values.

1. <em>Assume you have Food A, B, and C. Each has certain amount of Calcium, Iron, and Vit C. </em>

<em>             </em>Let's designate: Calcium <em>→ X oz , Iron → Y oz, vit C → Z oz</em>

2. <em>Assume you have following amount of</em><em> Calcium</em><em> in each food: </em>

  • Food A = 30 mg/oz
  • Food B = 25 mg/oz
  • Food C = 20 mg/oz

3. <em>Assume you have following amount of</em><em> Iron </em><em>in each food: </em>

  • Food A = 1 mg/oz
  • Food B = 1 mg/oz
  • Food C = 2 mg/oz

4. <em>Assume you have following amount of</em><em> vit C </em><em>in each food: </em>

  • Food A = 2 mg/oz
  • Food B = 5 mg/oz
  • Food C = 4 mg/oz

<u>Calculations:</u>

→ You have 3 different food and each has Calcium in it. You need exactly 320mg of Calcium per day. Therefore, each food would comprise certain proportion of daily Calcium intake. We can come up with equation: 30X+25Y+20Z = 390 mg

  • Similarly, for iron and vitamin C, the next equations could be used:

        X+Y+2Z=17 - Iron

        2X+5Y+4Z=42 - Vit C

→ Now you have a system of equations:

30X+25Y+20Z = 390 <em>(1) </em>

X+Y+2Z=17 <em>(2)</em>

2X+5Y+4Z=42 <em>(3)</em>

→ Look for similarities! <em>(1) and (3) </em>seem to be similar. We can multiply the <em>(3) </em>by -5 to obtain: -10X-25Y-20Z=-210. We add the <em>(1)</em> and modified <em>(3)</em> equations.

30X+25Y+20Z = 390

-10X-25Y-20Z=-210

__________________

20X+0+0=180

20X=180

<em><u>→ X=9 (oz of Calcium)</u></em>

<em><u></u></em>

→ Now, we can put<em> x=9 </em>into equations above to ease our job:

270+25Y+20Z=390 → 25Y+20Z=390-270=120

9+Y+Z=17 → Y+2Z=17-9=8

18+5Y+4Z=42 → 5Y+4Z=42-18=24

→ Similarly, we can use Eq-s <em>(2) and (3). </em>We can multiply the <em>(2) </em>by -5 to obtain: -5Y-10Z=-40. We add the <em>(3)</em> and modified <em>(2)</em> equations.

-5Y-10Z=-40

5Y+4Z=24

__________________

-6Z=-24

Z=4

<em><u>→ Z=4 (oz of vit C)</u></em>

<em><u></u></em>

→ Now, we can take X+Y+Z=17 <em>(2) </em>and just put in known values(<em>X=9 and Z=4</em>) to obtain Y:

9+Y+4=17

<u>→ Y=17-9-4=4 (oz of Iron)</u>

<u></u>

That's all! So, if you have table values, you can just re-write the equations and doing it stepwise, as it is shown here, you can manage to calculate every value you need :)

3 0
3 years ago
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