Perhaps (C), because ΔCAD ~= ΔXYZ.
let's firstly convert the mixed fractions to improper fractions and then add up all four days.
![\bf \stackrel{mixed}{16\frac{3}{4}}\implies \cfrac{16\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{67}{4}}~\hfill \stackrel{mixed}{12\frac{3}{4}}\implies \cfrac{12\cdot 4+3}{4}\implies \cfrac{47}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{all 4 days summed up}}{\cfrac{67}{4}+\cfrac{47}{4}}\implies \cfrac{67+47}{4}\implies \cfrac{114}{4}\implies \cfrac{57}{2}\implies 28\frac{1}{2}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B16%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B16%5Ccdot%204%2B3%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B67%7D%7B4%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B12%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B12%5Ccdot%204%2B3%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B47%7D%7B4%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Ball%204%20days%20summed%20up%7D%7D%7B%5Ccfrac%7B67%7D%7B4%7D%2B%5Ccfrac%7B47%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B67%2B47%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B114%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B57%7D%7B2%7D%5Cimplies%2028%5Cfrac%7B1%7D%7B2%7D)
Answer:
90
Step-by-step explanation:
If x = 4 is the Only Solution of the Equation x² + bx + 16 = 0
Then the Value x = 4 should satisfy the Given Equation
⇒ (4)² + b(4) + 16 = 0
⇒ 16 + 4b + 16 = 0
⇒ 4b + 32 = 0
⇒ 4b = -32
⇒ b = -8
Answer:
Yes??
Step-by-step explanation:
Whats the question? Is this your answer? <Confused>