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lubasha [3.4K]
3 years ago
7

The length of a rectangle is 2 units more than the width. The area of the rectangle is 48 units. What is the width, in units, of

the rectangle?
Mathematics
1 answer:
IRINA_888 [86]3 years ago
5 0

Answer:

6 units

Step-by-step explanation:

A = lw

l = w + 2

48 = lw

48 = (w + 2)w

48 = w² + 2w

0 = w² + 2w - 48

Quadratic equation results =

w = 6 or w = -8

But the measure could not be negative, therefore w = 6

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jeka57 [31]

Answer:

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4 0
3 years ago
Rory earned an 84% on his test. He answered 21 questions correctly. How many total questions were on the test? Round to the near
Free_Kalibri [48]

Answer:

25 questions

Step-by-step explanation:

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6 0
3 years ago
45 points for first most detailed / accurate answer:
Bas_tet [7]
A.) Since there are no restrictions as to the dimensions of the candle except that their volumes must equal 1 cubic foot and that each must be a cylinder, we have the freedom to decide the candles' dimensions. 

I decided to have the candles equal in volume. So, 1 cubic foot divided by 8 gives us 0.125 cubic foot, 216 in cubic inches.

With each candle having a volume of 216 cubic inches, I assign a radius to each: 0.5 in, 1.0 in, 1.5 in, 2.0 in, 2.5 in, 3.0 in, 3.5 in, and 4.0 in. Then, using the formula of the volume of a cylinder, which is:

V=pi(r^2)(h)

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Hence, we will have the following heights (expressed to the nearest hundredths) for each of the radius: for 

r=2.5 in: h=11.01 in
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r=4.5 in: h= 3.40 in
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b. each candle should sell for $15.00 each

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7 0
3 years ago
Label five places in the photo that have a slope.
Naya [18.7K]

Step-by-step explanation

The orange machine, the very end of the shovel part. That line is a slope. The middle part of the scooper could also be a slope. The very beginng part of the scooper is also a slope.  The bottom part of the scooper is also a slope. The bottom part at the end of the scooper could also be slope.

3 0
3 years ago
See Attached picture.
agasfer [191]
We use the Work formula to solve for the unknown in the problem which is W = F x d. First, we solve for the Net Force acting on the car. The Net Force is the summation of all forces acting on the object. For this case, we assume that Friction Force is negligible thus the Net Force is equal to:

F = mgsinα in terms of SI units and in terms of english units we have F = m(g/g₀)(sin α) where g₀ is the proportionality factor, 32.174 ft lb-m / lb-f s²

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W = Fd = 519.78 lb (400 ft) = 207912 ft - lb or 20800 ft-lb
5 0
3 years ago
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