They have free electron(s) on their outermost energy levels making them good conductors.
They have metallic bonds in their chemical structure.
They readily lose the electrons on their outermost energy levels, to bond with non-metals in ionic bonds to form chemical compounds called "salts"
Answer:
The correct answer is
[CH4][H2O]/[CO][H2]3
Option 3 is correct
Explanation:
Step 1: Data given
For the equation aA + bB ⇆ cC + dD
The equilibrium constant is [C]^c * [D]^d / [A]^a*[B]^b
Step 2: Calculate the equilibrium constant Kc
CO+3H2⇌CH4+H2O
Kc = [H2O][CH4] / [CO][H2]³
The correct answer is
[CH4][H2O]/[CO][H2]3
Option 3 is correct
Explanation:
It is given that 44.45 g of hydrocarbon gas produces 2649 kJ or 
of heat.
Also here, 1 lb = 453.592 g.
Therefore, amount of energy released by 453.592 g of hydrocarbon gas will be calculated as follows.
= 
It is known that 1 J = 
.
Hence, = 
= 7.508 Kwh
Thus, we can conclude that the combustion of exactly one pound of this hydrocarbon gas produce 7.508 Kwh energy.
Answer:
Quantum mechanical atomic model.
Explanation:
The first model of electronic configuration was given by Bohr's model.
The most accurate model of electronic configuration is the quantum mechanical atomic model.
Bohr's model has various limitations:
1. It does not explain the Zeeman effect and stark effect.
2. It is not valid for multi-electron system.
3. Heisenberg uncertainty principle is not followed by this model
The quantum mechanical atomic model explains all the four quantum numbers for the electronic configuration of an atom in the periodic table.
The quantum mechanical atomic model considered the Heisenberg uncertainty principle.
I think is energy passing and if its not im so sorry :(((
