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irinina [24]
3 years ago
15

What is the percent mass oxygen in calcium carbonate (CaCo3)?

Chemistry
2 answers:
Naily [24]3 years ago
7 0
20%ca,  80%br is the answer because it is the percent mass oxygen in calcium
Gnoma [55]3 years ago
4 0
  <span>Step 1 is to determine the mass of each part 
Mass of Ca is 40.08 g 
Mass of C is 12.01 g 
Mass of O is 16.00 x 3 = 48.00 g 
Step 2 is to determine the total mass of the compound 
Total mass of CaCO3 is 40.08 + 12.01 + 48.00 = 100.09 g 

Step 3 is to determine the % of each part using the following formula: 
Mass of part / total mass x 100 = 

40.08 / 100.09 x 100 = 40.04 % Ca 

12.01 / 100.09 x 100 = 12.00 % C 

48.00 / 100.09 x 100 = 47.96 % O 

Step 4 is to double check by adding all percentages. If they equal 100, then I probably did it right. :) 
40.04 
+12.00 
+47.96 
=100.00</span><span>
</span>
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Solution :

It is given that :

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It means that :

1 mol of $XBr_3$ contains = 3 mol of Br

∴ 3 mol of $Br^-$ contain in 1 mol of $XBr_3$

$4.834 \times 10^{-2}$ mol of $Br^-$  contains $1.576 \times 10^{-2}$ mol of $XBr_3$

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So $\text{molar mass}$ of $XBr_3$ = $\text{molar mass}$ of X + 3 x $\text{molar mass}$ of Br

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