Answer:
14.512g
Explanation:
Using the expression
mole = Number of molecules/6.022 x 10^23
mole of Fluorine = 2.30 x10^23/6.022 x 10^23
= 0.3819 mol
However,
mole = mass / molarmass
Mass of Fluorine = mole of Fluorine/ Molarmass of Fluorine
Molarmass of Fluorine = 18.998 x 2 = 37.996 g/mol
Mass of Fluorine = 0.3819mol/37.996g/mol
= 14.512g
You need to use q = mc(delta t)
<span>Solve for c: </span>
<span>c = q / m(delta t) </span>
<span>q = 55.o J </span>
<span>m = 11.0 g </span>
<span>delta t = 24.5 - 13.0 = 11.5 deg C </span>
<span>c = 55 J / 11.0 g)(11.5 C) </span>
<span>c = 0.435 J/ g C</span>
Answer:
Explanation:
The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
Consider the following reactions.
4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl
the oxidation state of copper is changed from +2 to +1 so copper get reduced.
CO + H₂O → CO₂ + H₂
the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.
Na₂CO₃ + H₃PO₄ → Na₂HPO₄ + CO₂ + H₂O
The oxidation state of carbon on reactant side is +4. while on product side is also +4 so it neither oxidized nor reduced.
H₂S + 2NaOH → Na₂S + 2H₂O
The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.
Oxidizing agents:
Oxidizing agents oxidize the other elements and itself gets reduced.
Reducing agents:
Reducing agents reduced the other element are it self gets oxidized
Answer:
183g
Explanation:
mass can't be created or destroyed so i think you just add up the total amounts of matter
