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2 years ago

Please help!!! Best answer will get brainliest

Chemistry

2 answers:

algol132 years ago

8 0

Mtallic

All the other answers don’t make sense

Effectus [21]2 years ago

5 0

The answer should be metallic

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What is the enthalpy of fusion of water?

malfutka [58]

Answer:

d- 334 kJ/g.

Explanation:

You can detect it from the units of the different choices.

a- has the unit J/g.°C that is the unit of the specific heat capacity (c).

b- has the unit Kelvin that is the unit of temperature.

c- has the unit g/mol which is the unit of the molar mass.

d- has the unit kJ/g which is the unit of the enthalpy divided by the no. of rams that is the specific entha;py of fusion.

<em>So, the right choice is: d- 334 kJ/g.</em>

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3 years ago

Gifblaar is a small South African shrub and one of the most poisonous plants known because it contains fluoroacetic acid (FCH2CO

PSYCHO15rus [73]

[H_{3}O^{+}] = 0.00770 M

The equilibrium equation representing the dissociation of $FCH_{2}COOH$

$FCH_{2}COOH(aq) + H_{2}O (l) FCH_{2}COO^{-}(aq)+ H_{3}O^{+}(aq)$

Given [H_{3}O^{+}] = 0.00770 M

Let the initial concentration of acid be x and change y

So y = $[H_{3}O^{+}]$ = $[FCH_{2}COO^{-}]$ = 0.00770 M

$pK_{a} = 2.59K_{a} = 10^{-2.59} = 0.00257 M$

$K_{a} = \frac{(0.00770 M)(0.00770 M)}{x - 0.00770}$

$0.00257 = \frac{0.00005929}{x - 0.00770}$

0.00257 x - 0.00001979 = 0.00005929

x = 0.031 M

Therefore, initial concentration of the weak acid is <u>0.031 M</u>

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3 years ago

Brian is testing to see how much water plants need. Why is it important that Brian includes a control group? A) To observe wheth

bija089 [108]

Answer: B or C

Explanation: The question does not include the variable or steps Brian is using so either one could be correct. It has to be the one that he is controlling though. This is because a control group is used to rule out any alternate explanations. Therefore the answer should be the one that he is trying to test out.

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2 years ago

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sergey [27]

Answer:

lose 1 2+

Explanation:

I honestly don't know

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2 years ago

If 3.50 L of propane at 24°C and 62.2 kPa is completely burned in excess oxygen, how many moles of carbon dioxide will be produc

Eva8 [605]

1) convert Celsius to Kelvin
24 + 273 = 297

2) convert kPa to atm
62.2 / 101.3 = 0.614

3) plug numbers into the ideal gas law formula

Answer: 0.088 mols

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3 years ago