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3 years ago

5

What amount of heat is required to raise the temperature of 20 grams of water from 10°C to 30°C? The specific heat of water is 4

.18 J/g°C.

1 answer:

gregori [183]3 years ago

8 0

Answer:

Explanation:

Heat = m*c * deltat

m = 20 grams

c = 4.19 J/g*C

deltaT = 30 - 10 = 20

Heat = 20 * 4.19 * 20

Heat = 1676 joules or 1.7 kJ depending on what you need.

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A tank of gas has partial pressures of nitrogen and oxygen equal to 1.61 Ã— 104 kPa and 4.34 Ã— 103 kPa , respectively.What is t

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Answer:

$20.44\times 10^3 kPa$ is the total pressure of the tank.

Explanation:

Partial pressures of nitrogen = $p_{N_2}=1.61\times 10^4 kPa$

Partial pressure of oxygen = $p_{O_2}=4.34\times 10^3 kPa$

Total pressure of gases in the tank = P

Applying Dalton's law of partial pressures :

$P=p_{N_2}+p_{O_2}=1.61\times 10^4 kPa+4.34\times 10^3 kPa$

$P=20.44\times 10^3 kPa$

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Answer:

$\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}$

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Hey there!

Sulfuric acid: H₂SO₄

H: 2 x 1.008 = 2.016

S: 1 x 32.065 = 32.065

O: 4 x 16 = 64

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The molar mass of sulfuric acid is 98.081 g/mol.

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