A 50.0 g sample of liquid water at 0.0°c ends up as ice at -20.0°c. How much energy is involved in this change.
1 answer:
Answer:
-4200J
Explanation:
Since q = mc∆T
where:
m = mass of the substance
c = specific heat capacity of the substance
∆T = change in temperature in Kelvin
but;
the specific heat capacity of water = 4.2J/K/g
Therefore q = 50*4.2*(253-273)
q = -4200J
Note: the negative is only used to indicate heat loss
Hope this helps
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