Question

What would be the mass in grams of 1.204 x 1024 molecules of sulfur dioxide

Answer 1

Answer:

mass of sulfur = 96 g

Explanation:

no of moles of sulfur dioxide in $1.204\times 10^{24}$ molecules = $\frac{1.204\times 10^{24}}{avagadro number }= \frac{1.204\times 10^{24}}{6.023\times 10^{23}}$

                                       = 2 moles

therefore mass of sulfur dioxide = moles×atomic number

                                                      =2×(16+32)

                                                      =96