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V125BC [204]
3 years ago
13

What would be the mass in grams of 1.204 x 1024 molecules of sulfur dioxide

Chemistry
1 answer:
melomori [17]3 years ago
6 0

Answer:

mass of sulfur = 96 g

Explanation:

no of moles of sulfur dioxide in 1.204\times 10^{24} molecules = \frac{1.204\times 10^{24}}{avagadro number }= \frac{1.204\times 10^{24}}{6.023\times 10^{23}}

                                       = 2 moles

therefore mass of sulfur dioxide = moles×atomic number

                                                      =2×(16+32)

                                                      =96

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Answer:

Explanation:

412 ATP's will be generated from the complete metabolic oxidation of tripalmitin (tripalmitoylglycerol)

130 ATP from the oxidation of palmitate

22 ATP from the oxidation of glycerol

Altogether 130 + 22 = 412 ATP will be produced.

Here in case of tripalmitin (tripalmitoylglycerol), we have 51 carbons.

When 51 carbons can produce 412 ATPs

Then 1 carbon will produce how many ATPs = 412 ATPs/ 51 carbon= 8.1 ATPs.

This shows that ATP yield per carbon often oxidized will be 8.1 ATPs

Now we will see the ATP yield in the case of glucose.

Glucose is made up of 6 carbon and complete oxidation of glucose will produce 38 ATPs

When 6 carbons can yield 38 ATPs

Then 1 carbon can yield how many ATPs= 38 ATPs/ 6 carbons= 6.33 ATPs.

So, ATP yield per carbon in case of glucose will be 6.33 ATPs

8 0
3 years ago
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True

Explanation:

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Explanation:

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2 years ago
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the density of water at different temperature is listed in the table above. Based on this information we can predict that the de
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3 years ago
A 0.105 L sample of an unknown HNO 3 solution required 35.7 mL of 0.250 M Ba ( OH ) 2 for complete neutralization. What is the c
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Answer: 0.17M

Explanation:

The equation for the reaction is :

2HNO3 + Ba(OH)2 —> Ba(NO3)2 + 2H2O

From the balanced equation, we obtain :

nA = mole of acid = 2

nB = mole of the base = 1

From the question, we obtain:

Va = Vol. Of acid = 0.105L

Ma = conc. Of acid =?

Vb = Vol of base = 35.7 mL = 0.0357L

Mb = conc. of base = 0.25M.

We solve for the conc. of the acid using:

MaVa / Mb Vb = nA / nB

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Cross multiply to express in linear form. We have:

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Divide both side by 0.105. We have

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