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3 years ago

What would be the mass in grams of 1.204 x 1024 molecules of sulfur dioxide

Chemistry

1 answer:

melomori [17]3 years ago

6 0

Answer:

mass of sulfur = 96 g

Explanation:

no of moles of sulfur dioxide in $1.204\times 10^{24}$ molecules = $\frac{1.204\times 10^{24}}{avagadro number }= \frac{1.204\times 10^{24}}{6.023\times 10^{23}}$

= 2 moles

therefore mass of sulfur dioxide = moles×atomic number

=2×(16+32)

=96

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What information can be found on a diagram of the earths energy budget

Yanka [14]

Answer:

Explanation:

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bazaltina [42]

Answer:

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Explanation:

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3 years ago

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Liquid octane CH3CH26CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O . Suppose

Slav-nsk [51]

Answer:

The minimum mass of octane that could be left over is 43.0 grams

Explanation:

Step 1: Data given

Mass of octane = 73.0 grams

Mass of oxygen = 105.0 grams

Molar mass octane = 114.23 g/mol

Molar mass oxygen = 32.0 g/mol

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate the number of moles

Moles = mass / molar mass

Moles octane = 73.0 grams / 114.23 g/mol

Moles octane = 0.639 moles

Moles O2 = 105.0 grams / 32.0 g/mol

Moles O2 = 3.28 moles

Step 4: Calculate the limiting reactant

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

O2 is the limiting reactant. It will completely be consumed. (3.28 moles). There will react 3.28 / 12.5 = 0.2624 moles. There will remain 0.639 - 0.2624 = 0.3766 moles octane

Step 5: Calculate mass octane remaining

Mass octane = moles * molar mass

Mass octane = 0.3766 moles * 114.23 g/mol

Mass octane = 43.0 grams

The minimum mass of octane that could be left over is 43.0 grams

3 0

3 years ago

A chemistry graduate student is given 500. mL of a 0.20 M chloroacetic acid (HCH2ClCO2) solution. Chloroacetic acid is a weak ac

zhenek [66]

Answer:

12 g of choloracetic acid

Explanation:

The buffer equilibrium is:

HCH₂ClCO₂ ⇄ CH₂ClCO₂⁻ + H⁺

pka= -log ka =

Ka: 1,3x10⁻³ = [CH₂ClCO₂⁻] [H⁺] / [HCH₂ClCO₂]

By Henderson-Hasselbalch equation:

pH = pka + log₁₀ [A⁻] / [HA]

3,01 = 2,89 + log₁₀ [A⁻] / [HA]

1,318 = [A⁻] / [HA]

As molar concentration of chloroacetic acid (HA) is 0,20M

[A⁻] = 0,26 mol/L

The volume is 500 mL ≡ 0,5 L

0,26mol/L × 0,5 L = 0,13 moles of chloroacetic acid. In grams:

0,13 mol × (94,5g / 1mol) = <em>12 g of choloracetic acid</em>

I hope it helps!

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4 years ago

Give an example of how natural selection could benefit a species. Justify your response in two or more complete sentences.

PolarNik [594]

Natural selection can benefit a species in many ways. One way natural selection benefits a species is by helping a species adapt to constant changing environments and biomes. natural selection can also benefit a species by dying of the weaker links of a species and adapting the mutated species. hope this helped! :)

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3 years ago