Changes in matter occur every day. There are two types of ways matter can be altered; physically and chemically. Physical changes do not change the composition of the matter while chemical changes occur when one or more substances turn into a completely new substance. Physical changes can be seen through an altering of the substances physical property. A substances physical property is observed and measured without changing the composition of the subject. Descriptive words that would help to identify a substance’s physical property include hard, soft, brittle, flexible, heavy, and light just to name a few. Let’s say you’re eating, throughout the day your stomach starts to growl that is what happens when your stomach is digesting your food. Digestion is an example of chemical change. Chemical change happens every day and more than half the time we don’t realize it whether it’s metal starting to rust, or our food starting to rot. Physical change can happen when your popsicle starts to melt, or your water starting starting to boil. These are examples of physical change.
Answer: -
9270 grams
Explanation: -
Number of molecules of C₆H₁₂O₆ = 3.25 x 10 ²⁶
According to Avogadro's law,
6.02 x 10 ²³ molecules of C₆H₁₂O₆ are present in 1 mole of C₆H₁₂O₆
3.25 x 10 ²⁶ molecules of C₆H₁₂O₆ are present in of C₆H₁₂O₆
= 54 mol of C₆H₁₂O₆
Molar mass of C₆H₁₂O₆ = 12 x 6 + 1 x 12 + 16 x 6 = 180g /mol
Mass of C₆H₁₂O₆ = 54 mol x 180g /mol
= 9270 g
Answer:
.574
Explanation:
smallest number of digits in the expression was 3, so the final answer should have 3 sig figs
Answer: The correct option is C.
Phosphorus has no atmospheric component.
Explanation:
This is because, phosphorus is not in gaseous state but it is liquid at normal temperature, therefore it cannot be found in the air. It is cycle through water,soil or sediments. The major source of phosphorus in the phosphorus cycle is the rock. Rock contain phosphorus and phosphorus I'd gotten from rocks through weathering. Weathering is the disintegration of rocks into sediments or smaller particles. This is released into the soil after weathering.
Answer: V2= 41.2mL
Explanation:
Givens:
* V1= 20ml
* T1 = -109 ⁰C --> K= ⁰C + 273.15 --> 164.15 K
* V2 = ??
* T2= 338.15 K
Use Charles law V1/T1 = V2/T2
Since we are looking for V2 we can rearrange the formula to
V2= (T2 x V1) /T1
V2= (338.15K x 20mL) / 164.15 K
V2= 41.2mL
NOTE:
Temperature should always be in K not in ⁰C or ⁰F
To convert from C to K use
*K= ⁰C + 273.15
Enter your C value in the ( ⁰C ) and you can get K