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OLga [1]
4 years ago
15

Sometimes you are given a measured amount of two or more reactants and asked how much product can be formed. Explain what steps

you would follow to solve this type of problem.
Chemistry
1 answer:
Westkost [7]4 years ago
4 0

Explanation:

To solve this problem, follow these steps;

  • Obtain a balanced equation of the reaction and familiarize with the reactants and products.
  • Find the number of moles of the reacting species since they are the known matter in terms of quantity.
  • From the number of moles, determine the limiting reactant.
  • The limiting reactant is the one given in short supply.
  • Such reactant determines the extent of the reaction.
  • Compare the moles of this specie to that of the products using the balanced equation.
  • Obtain the mole of the desired product and find the mass or desired quantity.
  • simply work from the known specie to the unknown

learn more:

Number of moles brainly.com/question/13064292

#learnwithBrainly

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If I use the dropper to add 10 mL of drink mix to 50 mL of water, what is the
Yuliya22 [10]

Answer:

16.7%

Explanation:

From the question given above, the following data were obtained:

Volume of drink mix = 10 mL

Volume of water = 50 mL

Percentage of drink mix =?

Next, we shall determine the total volume of the solution. This can be obtained as follow:

Volume of drink mix = 10 mL

Volume of water = 50 mL

Total volume of solution =?

Total volume of solution = (Volume of drink mix) + (Volume of water)

Total volume of solution = 10 + 50

Total volume of solution = 60 mL

Finally, we shall determine the percentage of the drink mix in the solution. This can be obtained as follow:

Volume of drink mix = 10 mL

Total volume of solution = 60 mL

Percentage of drink mix =?

Percentage of drink mix = Vol. of drink mix / total volume × 100

Percentage of drink mix = 10/60 × 100

Percentage of drink mix = 16.7%

4 0
3 years ago
3. Given 20g of Barium Hydroxide, how many grams of
anastassius [24]

The number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

First, we will write the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

Ba(OH)₂ + 2NH₄NO₃ → 2NH₄OH + Ba(NO₃)₂

This means, 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Now, we will calculate the number of moles of barium hydroxide present.

Mass of barium hydroxide (Ba(OH)₂) = 20 g

Using the formula

Number\ of\ moles = \frac{Mass}{Molar\ mass}

Molar mass of Ba(OH)₂ = 171.34 g/mol

∴ Number of moles of Ba(OH)₂ present =\frac{20}{171.34}

Number of moles of Ba(OH)₂ present = 0.116727 mole

Now,

Since 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Then,

0.116727 mole of barium hydroxide will react with 2 × 0.116727 mole of ammonium nitrate

2 × 0.116727 = 0.233454 mole

∴ Number of moles of NH₄NO₃ required is 0.233454 mole

Now, for the mass of ammonium nitrate (NH₄NO₃) required

From the formula

Mass = Number of moles × Molar mass

Molar mass of NH₄NO₃ = 80.043 g/mol

∴ Mass of NH₄NO₃ required = 0.233454 × 80.043

Mass of NH₄NO₃ required = 18.68636 g

Mass of NH₄NO₃ required ≅ 18.7g

Hence, the number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

Learn more on determining mass of reactant required here: brainly.com/question/11232389

6 0
2 years ago
The specific heat capacity of an unknown metal is 0.343 J/(g•°C). Calculate the energy required to raise the temperature of 224
Margarita [4]

Explanation:

the answer and explanation is in the picture

hope this helps

please like and Mark as brainliest

8 0
4 years ago
Which of these can be described as a system of stars, gases, dust, and other matter that orbits a common center of gravity?
velikii [3]
It’s c galaxy ((: so yeah
8 0
3 years ago
Read 2 more answers
In the following reaction, how many grams of ammonia (NH3) will react with 27.8 grams of nitric oxide (NO)? 4NH3 + 6NO → 5N2 + 6
Rzqust [24]
<span>4NH</span>₃<span> + 6NO → 5N</span>₂<span> + 6H</span>₂<span>O

mol of NO  =  </span>\frac{mass of NO}{Molar Mass of NO}
 
                  =  \frac{27.8 g}{30.01 g / mol}
                   
                  =  0.93 mol

Based on the balance equation mole ratio of NH₃  :  NO  is   4 : 6
                                                                                            =  2 : 3

If mol  of NO  =  0.93 mol

then mol of NH₃ = \frac{0.93 mol  *  2}{3}
                           
                          =  0.62 mol

Mass of ammonia =  mol  ×  molar mass
          
                             =  0.62 mol   ×  17.03 g/mol
 
                             =  10.54 g

Therefore B is the best answer





3 0
3 years ago
Read 2 more answers
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