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2 years ago

What neutral element will have the electron configuration 1s22s22p63s23p1?

Chemistry

1 answer:

Dovator [93]2 years ago

3 0

Answer:

a. aluminum

Explanation:

Given electronic configuration:

1s² 2s² 2p⁶ 3s² 3p¹

The number of electrons can be determined from adding the powers or superscripts.

Since we are dealing with a neutral element, the number of electrons and protons are the same. So we can determine the atomic number which is the number of protons.

Number of electrons = 2 + 2 + 6 + 2 + 1 = 13

The element with atomic number 13 is aluminum.

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What is the associated deBroglie wavelength of a H2 molecule moving on one direction with kinetic energy of (3/2 kT) at 30 K

andrey2020 [161]

<u>Answer:</u> The de-Broglie's wavelength of a hydrogen molecule is $3.26\AA$

<u>Explanation:</u>

Kinetic energy is the measure of temperature of the system.

The equation used to calculate kinetic energy of a particle follows:

$E=\frac{3}{2}kT$

where,

E = kinetic energy of the particles = ?

k = Boltzmann constant = $1.38\times 10^{-23}J/K$

T = temperature of the particle = 30 K

Putting values in above equation, we get:

$E=\frac{3}{2}\times 1.38\times 10^{-23}J/K\times 30K\\\\E=6.21\times 10^{-22}J$

Calculating the mass of 1 molecule of hydrogen gas:

Conversion factor used: 1 kg = 1000 g

1 mole of hydrogen gas has a mass of 2 grams or $2\times 10^{-3}kg$

According to mole concept:

$6.022\times 10^{23}$ number of molecules occupy 1 mole of a gas.

As, $6.022\times 10^{23}$ number of hydrogen molecules has a mass of $2\times 10^{-3}kg$

So, 1 molecule of hydrogen will have a mass of = $\frac{2\times 10^{-3}kg}{6.022\times 10^{23}}\times 1=3.32\times 10^{-27}kg$

To calculate the wavelength of a particle, we use the equation given by De-Broglie's wavelength, which is:

$\lambda=\frac{h}{\sqrt{2mE_k}}$

where,

$\lambda$ = De-Broglie's wavelength = ?

h = Planck's constant = $6.624\times 10^{-34}Js$

m = mass of 1 hydrogen molecule = $3.32\times 10^{-27}kg$

$E_k$ = kinetic energy of the particle = $6.21\times 10^{-22}J$

Putting values in above equation, we get:

$\lambda=\frac{6.624\times 10^{-34}Js}{\sqrt{2\times 3.32\times 10^{-27}kg\times 6.21\times 10^{-22}J}}$

$\lambda=3.26\times 10^{-10}m=3.26\AA$ (Conversion factor: $1\AA=10^{-10}m$ )

Hence, the de-Broglie's wavelength of a hydrogen molecule is $3.26\AA$

3 0

2 years ago

Addition of a catalyst can speed up a reaction by providing an alternate reaction pathway that has a

kkurt [141]

Answer:

Addition of a catalyst can speed up a reaction by providing an alternate reaction pathway that has a lower activation energy

Explanation:

A catalyst is an agent that increases the rate of a chemical reaction by providing an alternate pathway for the reaction that requires a lower activation energy. As the requirement for activation energy is less in the presence of a catalyst, there are more reactant particles becoming involved in the chemical reaction and as such there are more products formed per unit time, or there is an increase in the rate of the reaction

Example of catalyst include

1. Addition of potassium permanganate to hydrogen peroxide to aid in the rapid decomposition into water and oxygen

2. Platinum serves as a catalyst in the complete combustion of carbon monoxide into carbon dioxide.

5 0

2 years ago

All the mixture are harmful for us. is this statement true? justify with two examples

Taya2010 [7]

Answer:

no.it is false.some are useful.like mixture of h2 and O 2 to form water.

3 0

2 years ago

Read 2 more answers

3. compounds in which elements are held together by covalent bonds...keeps their own properties

stich3 [128]

The anserr is c that what i think

3 0

3 years ago

Serine has pka1 = 2.21 and pka2 = 9.15. use the henderson-hasselbalch equation to calculate the ratio neutral form/protonated fo

malfutka [58]

Calculate the ratio by using Henderson-Hasselbalch equation:

pH = pKa + log [neutral form] / Protonated form

3.05 = 2.21 + log [neutral form] / [Protonated form]

3.05 - 2.21 = log [neutral form] / [Protonated form]

0.84 = log [neutral form] / [Protonated form]

[neutral form] / [protonated form] = anti log 0.84 = 6.91

8 0

3 years ago