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defon
3 years ago
8

Whicl ordered pair makes the inequality true? X+y>8

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0
Some ordered pairs are:(10,5), (0,9), and (3,15) that make the equation true.
Hope this helps!! ::))
Please rate as brainliest (if it helped at all)!! ::))
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The dot plot below shows the number of students on a classroom honor roll for one or more weeks. According to the dot plot how m
d1i1m1o1n [39]
Three times more of the week were plotted
5 0
2 years ago
Lars deposited $50 into a savings account for which interest is compounded quarterly. According to the rule of 72, what interest
Ivanshal [37]

Answer: C 2.5%


Step-by-step explanation:

The "Rule of 72" is a easy way to calculate how much time an investment will take to double with a given fixed annual rate of interest.

Just we have to divide 72 by the annual rate of return(r), we can get a rough estimate of how many years it will take to double the initial investment .

Now, in given problem: Let 'r' be the rate of interest

Time to double the amount=29 years

Thus by rule 72 ,

\frac{72}{r}=29\\\Rightarrow\ r=\frac{72}{29}=2.4827\%\approx2.5\%

Therefore, C is the right option.


3 0
3 years ago
Read 2 more answers
Plz help me. im not as smart as I seem. 7th grade math. extra points!
Strike441 [17]
Okay what’s the question?
7 0
3 years ago
For the love of God help me !! I'm desperate for it tomorrow
Eduardwww [97]
Try to relax.  Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before.  But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.

Consider this:  (2)^a negative power = (1/2)^the same power but positive.

So: 
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.

What I just said in that paragraph was:  log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.

Now let's look at the problem:

log₂(x-1) + log(base 1/2) (x-2) = log₂(x)

Subtract  log₂(x)  from each side: 

log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0

Subtract  log(base 1/2) (x-2)  from each side:

log₂(x-1) - log₂(x)  =  - log(base 1/2) (x-2)  Notice the negative on the right.

The left side is the same as  log₂[ (x-1)/x  ]

==> The right side is the same as  +log₂(x-2)

Now you have:  log₂[ (x-1)/x  ]  =  +log₂(x-2)

And that ugly [ log to the base of 1/2 ] is gone.

Take the antilog of each side:

(x-1)/x = x-2

Multiply each side by 'x' :  x - 1 = x² - 2x

Subtract (x-1) from each side:

x² - 2x - (x-1) = 0

x² - 3x + 1 = 0

Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .

I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.


There,now.  Doesn't that feel better. 
 






4 0
3 years ago
Which one is right triangle angle <br>a. 45, 55 and 35<br>b. 52, 48 and 20​
Gemiola [76]
<h2>option b. 52, 48 and 20</h2>

Step-by-step explanation:

<u>let's solve:-</u>

  • To test whether given this triangle is right triangle or not, we can use the Pythagorean Theorem .

soo

Pythagorean Theorem=

\bold \green{(leg1)^{2} +(leg2)^{2} =(hypotenuse)^{2} }

<h2>_____________________________________</h2>

Here:-

\bold \blue{leg \: 1 = 48} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\ \bold  \blue{ leg2 = 20} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \bold\blue{hypotenuse = 52}

Putting values:-

{48}^{2}  +  {20}^{2}  = {52}^{2}   \:  \:  \:  \:  \:  \: \\  \\ 2304 + 400 = 2704 \\  \\ 2704 = 2704 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

<h2>_____________________________________</h2>
4 0
2 years ago
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