What sample of matter has a crystalline structure?

5000kg of ammonium nitrate per square kilometer of cornfield per year. how much nitric acid would be needed to make the fertiliz

Serggg [28]

$NH_3+HNO_3-> NH_4NO_3$

1 mole of nitric acid produce 1 mole of ammonium nitrate.

moles in 5000 kg of ammonium nitrate :

$n=\dfrac{5000\times 1000}{80}\\\\n=62500\ moles$ ( molecular mass of ammonium nitrate is 80 gm/mol )

So, number of moles of nitric acid required are also 62500 moles.

Mass of 62500 moles of nitric acid :

$mass = 62500\times 63 \\\\mass = 3937500\ gram\\\\mass = 393.75\ kg$

Hence, this is the required solution.

5 0

2 years ago

1. When an acid reacts with a base, what compounds are formed? (1 point) a salt only water only metal oxides only a salt and wat

scoundrel [369]

Answer: 1) only a salt and water

An acid and base reacts together to undergo neutralization to form salt and water.

$HCl+NaOH\rightarrow NaCl+H_2O$

where HCl is an acid and NaOH is a base to form salt (NaCl) and water $(H_2O)$ .

Answer: 2) The formula of the hydrogen ion is often written as $H^+$ .

All acids dissociate in water to give $H^+$ ions.

Answer: 3) Arrhenius acids are substances that ionizes to yield protons in aqueous solution.

$HCl\rightarrow H^++Cl^-$

Arrhenius bases are substance that ionizes to yield hydroxide ions in aqueous solution.

$NaOH\rightarrow Na^++OH^-$

Answer: 4) A conjugate acid base pair transfers hydrogen ion.

$CH_3COO^-+H_2O\rightarrow CH_3COOH+H_3O^+$

Here $CH_3COO^-$ accepts a proton and thus act as a base and the corresponding $CH_3COOH$ is its conjugate acid.

Answer: 5) Bronsted Lowry acid is a substance that donates protons. Bronsted Lowry base is a substance that accepts protons.

$NH_4^+$ and $NH_3$

$NH_3+H^+\rightarrow NH_4^+$

$NH_3$ is a acid which accepts proton and thus acts as base to form conjugate acid $NH_4^+$ .

4 0

2 years ago

Read 2 more answers

A 10.0 L balloon contains helium gas at a pressure of 655 mmHg. What is the final pressure, in millimeters of mercury, if the fi

joja [24]

Answer:

474.64mmHg

Explanation:

From the question given, we obtained the following:

V1 = 10L

P1 = 655mmHg

V2 = 13.8L

P2 =?

P1V1 = P2V2

10 x 655 = P2 x 13.8

Divide both side by the coefficient P2 i.e 13.8

P2 = (10 x 655) / 13.8

P2 = 474.64mmHg

Therefore, the new pressure will be 474.64mmHg

7 0

2 years ago

A chemist measures the energy change ?H during the following reaction: 2HgO (s) ?2Hg (l) +O2 (g) =?H182.kJ Use the information t

Elan Coil [88]

Answer:

A. endothermic.

A. Yes, absorbed.

Explanation:

Let's consider the following thermochemical equation.

2 HgO(s) ⇒ 2 Hg(l) + O₂(g) ΔH = 182 kJ

The enthalpy of the reaction is positive (ΔH > 0), which means that the reaction is endothermic.

182 kJ are absorbed when 2 moles of HgO react (molar mass 216.59 g/mol). The heat absorbed when 72.8 g of HgO react is:

$72.8g.\frac{1mol}{216.59g} .\frac{182kJ}{2mol} =30.6kJ/mol$

6 0

2 years ago

If 11g of a gas occupies 5.6dm'3at s.t.p., calculate it's vapour density (1.0mol of a gas occupies 22.4dm'3at s.t.p.).

11111nata11111 [884]

Answer:

${ \boxed{ \bf{vapour \: density = 2 \times molecular \: mass}}} \\{ \tt{ PV= (\frac{m}{ m_{r}}) RT}} \\ { \tt{3 \times 5.6 = \frac{11}{m _{r}} \times 0.0831 \times 273}} \\ { \tt{m _{r} = 14.85 \: g}} \\ \\ { \bf{vapour \: density = 2 \times m _{r}}} \\ = 2 \times 14.85 \\ = 29.7 \: { \tt{g {dm}^{ - 3} }}$

7 0

2 years ago