Answer:
a) NH3/NH4Cl (pKa = 9.25)
b) ![\frac{[Base]}{[Acid]} =0.708](https://tex.z-dn.net/?f=%5Cfrac%7B%5BBase%5D%7D%7B%5BAcid%5D%7D%20%3D0.708)
c)
Explanation:
Hello,
a) In this case, for a buffering capacity, if we want to select the best buffer, we should ensure that the buffer's pKa approaches the desired pH, therefore, since the buffer NH3/NH4Cl has a pKa of 9.25 that is very close to the desired pH of 9.10, we can pick it as the best choice.
b) In this case, we use the Henderson-Hasselbach equation in order to compute the molar ratio:
![pH=pKa+log(\frac{[Base]}{[Acid]} )\\\\log(\frac{[Base]}{[Acid]} )=9.10-9.25=-0.15\\\\\frac{[Base]}{[Acid]} =10^{-0.15}\\\\\frac{[Base]}{[Acid]} =0.708](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5BBase%5D%7D%7B%5BAcid%5D%7D%20%29%5C%5C%5C%5Clog%28%5Cfrac%7B%5BBase%5D%7D%7B%5BAcid%5D%7D%20%29%3D9.10-9.25%3D-0.15%5C%5C%5C%5C%5Cfrac%7B%5BBase%5D%7D%7B%5BAcid%5D%7D%20%3D10%5E%7B-0.15%7D%5C%5C%5C%5C%5Cfrac%7B%5BBase%5D%7D%7B%5BAcid%5D%7D%20%3D0.708)
c) Finally, for the ratio of masses, we use the molar mass of both ammonia as the base (17 g/mol) and ammonium chloride as the acid (53.45 g/mol) to compute it, assuming 1.00 L as the volume of the solution:

Regards.