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Dovator [93]
3 years ago
10

A chemist measures the energy change ?H during the following reaction: 2HgO (s) ?2Hg (l) +O2 (g) =?H182.kJ Use the information t

o answer the following questions. This reaction is...
A. endothermic.
B. exothermic.

Suppose 72.8g of HgO react. Will any heat be released or absorbed?

A. Yes, absorbed.
B. Yes, released.
C. No.
Chemistry
1 answer:
Elan Coil [88]3 years ago
6 0

Answer:

A. endothermic.

A. Yes, absorbed.

Explanation:

Let's consider the following thermochemical equation.

2 HgO(s) ⇒ 2 Hg(l) + O₂(g)  ΔH = 182 kJ

The enthalpy of the reaction is positive (ΔH > 0), which means that the reaction is endothermic.

182 kJ are absorbed when 2 moles of HgO react (molar mass 216.59 g/mol). The heat absorbed when 72.8 g of HgO react is:

72.8g.\frac{1mol}{216.59g} .\frac{182kJ}{2mol} =30.6kJ/mol

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maxonik [38]

Answer:

3. Which side of the chain should you count from when naming organic compounds?

C) Side that will give you the longest Carbon chain

4. What is the pH of a solution with a pOH of 10?

C) 4

pH + pOH = 14

pH + 10 = 14

pH = 14 - 10

pH = 4

<u>-TheUnknownScientist</u>

3 0
3 years ago
During combustion, methane yields carbon dioxide and water. The unbalanced equation for this reaction is:CH4(g)+O2(g) → CO2(g)+
almond37 [142]

Answer:

CH₄(g)  +  2O₂(g) → CO₂(g)  +  2H₂O(l)

Mole ratios for the balanced equation be:

1:2, 2:1, 1:1, 1:2, 2:2

Explanation:

CH4(g)+O2(g) → CO2(g)+ H2O(l)

To balance a chemical equation, you must have the same mole of each element in both sides of the reaction (reactant side and product side)

CH₄(g)  +  2O₂(g) → CO₂(g)  +  2H₂O(l)

2 C

8 H

8 O

In  both side.

It takes 1 mole of methane to react with 2 mole of oxygen in order to produce 1 mol of dioxide and 2 mole of water.

Mole ratios for the balanced equation be:

Mole ratios for the balanced equation be:

1:2, 2:1, 1:1, 1:2, 2:2  - We should compare each compound

1 mol methane → 2 mole of oxygen

2 mole of oxygen → 1 mol of methane

2 mole of oxygen → 1 mol of dioxide

1 mole of dioxide → 1 mol of Methane

2 mole of water → 2 mole of oxygen (the same as opposite)

1 mol methane →  2 mole of water

2 mol of water → 1 mol of methane

4 0
3 years ago
A 53. 5 mL ample of an 5. 4 % (m / v) KBr olution i diluted with water o that the final volume i 205. 0 mL Expre your anwer to t
gogolik [260]

The concentration after dilution is 1.4%.

We are aware that concentration and volume are related to each other by the formula -

C_{1} V_{1} = C_{2} V_{2}, where we have initial concentration and volume on Left Hand Side and final concentration and volume on Right Hand Side.

Keep the values to calculate final concentration.

C_{2} = (53.5 × 5.4)/205.0

Performing multiplication on Right and Side

C_{2} = 288.9/205.0

Performing division on Right Hand Side

C_{2} = 1.4%

Hence, the final concentration is 1.4%.

Learn more about concentration -

brainly.com/question/17206790

#SPJ4

The complete question is -

A 53.5 mL sample of an 5.4 % (m/v) KBr solution is diluted with water so that the final volume is 205.0 mL.

Calculate the final concentration and express your answer to two significant figures and include the appropriate units.

3 0
1 year ago
How many moles are in 25 g KMnO4
Ronch [10]

Answer:

0.158 moles KMnO4

Explanation:

According to the Periodic Table,

K = 39.10 g/mol

Mn = 54.94 g/mol

O = 16.00 g/mol

KMnO4 = 39.10 g/mol + 54.94 g/mol + 4(16.00 g/mol) = 158.04 g/mol

25.0 grams KMnO4              1 mole

-----------------------------  x --------------------------  = 0.158 moles KMnO4

                                          158.04 grams

8 0
2 years ago
Calculate the hydroxide ion concentration of a 0.200 M solution of HCIO4
Aleksandr [31]

The concentration of hydroxide ion is  5  \times 10^ − 14  M.

<u>Explanation:</u>

Consider the equilibrium of this acid's dissociation,

                          H C l O 4  ⇌  H +  +  C l O  4 -

Moreover, let's assume that  H C l O 4  is a strong acid and will fully dissociate.

Hence,

                              [ H + ]  =  0.20  M

Now, recall,  

                  K w  =  [ H + ] [ O H − ]  =  1.0  \times 10 ^− 14

Hence,

                  ⇒ [ O H − ]  =  K w  / [ H + ]  = 5  \times 10^ − 14  M.

7 0
3 years ago
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