Answer: 878 kJ of energy is there in cheeseburger
Explanation:
Given : calorific value of fat = 38kJ/g
calorific value of carbohydrate = 17 kJ/g
calorific value of protein = 17kJ/g
1 g of fat contains energy = 38 kJ
7.0 g of fat contains energy =
1 g of carbohydrate contains energy = 17 kJ
25 g of fat contains energy =
1 g of protein contains energy = 17 kJ
11 g of protein contains energy =
Total energy = (266+425+187) kJ = 878 kJ
Explanation:
Since, it is given that critical temperature of Argon is 150.9 K and critical pressure of Argon is 48.0 atm.
It is known that gas phase of neon occurs at 50 K. As the boiling point of Ar is more than the boiling point of neon which means that there is strong intermolecular force of attraction between argon molecules as compared to neon molecules.
This is also because argon is larger in size. As a result, induced dipole-induced dipole forces leads to more strength in Ar as compared to Ne.
The element that was oxidized is carbon, as it’s oxidation state increased (electrons were lost) from +2 (in the reactants) to +4 (in the products). The element that was reduced is nitrogen, as it gained electrons and went from a +2 oxidation state (reactants) to a 0 oxidation state (products). Since the carbon was oxidized and it’s electrons were used to reduce the nitrogen, carbon is the reducing agent.
Answer:
a)23.2 L
b)68.3kPa
c)7.5 atm
d)60.5L
e)1.67 atm
Explanation:
From Boyle's law:
P1V1=P2V2
P1= 748mmHg
P2=725mmHg
V1= 22.5L
V2??
V2= P1V1/P2= 748×22.5/725= 23.2 L
b)
V1=4.0L
P1= 205×10^3Pa
V2= 12.0L
P2=???
P2= P1V1/V2= 205×10^3×4/12
P2= 68.3×10^3 Pa or 68.3kPa
c)
P1= 1 atm
V1= 196.0L
P2= ??
V2= 26.0L
P2= P1V1/V2=1×196.0/26.0
P2= 7.5 atm
d)
V1= 40.0L
P1= 12.7×10^3Pa
V2=???
P2= 8.4×103Pa
V2= P1V1/P2= 12.7×10^3×40.0/8.4×103
V2=60.5L
e)
V1= 100mL
P1= 1atm
V2= 60mL
P2=???
P2= P1V1/V2= 1×100/60
P2= 1.67 atm