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ki77a [65]
2 years ago
10

Please somone help me with a chemistry question brainliest to whoever answers correctly and 20 points

Chemistry
1 answer:
zzz [600]2 years ago
5 0

Answer:

289.15k is the answer buddy

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Four different objects are placed on a number line at 0. The chart describes the motion of each object. Using the information in
mote1985 [20]

The chart with the information to answer this question may be found in other Brainly's link, so I attach it now.

Answer:

  • Z

Explanation:

To facilitate the accompaniment of the reasoning, I copy the data here:

Object     Motion

  X           3 units left, 3 units right

  Y           6 units right, 18 units right

  W          8 units left, 24 units right

  Z          16 units right, 8 units left

The <em>distance</em> is the scalar magnitude that indicates the total length of the path traveled.

The <em>displacement</em> is the vector that indicates how far the end point and the initial point are.

In order to calculate the distance, the displacement and the ratio r = distance/displacement, to check which object has a distance that is three times as great as its displacement, i.e. r = 3, we use this new chart:

Object    Motion                                    Distance     Displacement  ratio

  X          3 units left, 3 units right        3 + 3 = 6       3 - 3 = 0            ∞

  Y          6 units right, 18 units right    6 + 18 = 24    6 + 18 = 24       1

  W         8 units left, 24 units right      8 + 24 = 32   -8 + 24 = 16     2

  Z          16 units right, 8 units left       16 + 8 = 24    16 - 8 = 8         3

The ratios were calculated dividing the distance by the displacement: distance / displacement.

For the object Z, that was 24 / 8 = 3. Thus, the object that has a distance that is three times as great as its displacement is the object Z.

8 0
3 years ago
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3 0
3 years ago
The atmosphere's variable gases that most influence the greenhouse effect are _____. nitrogen and oxygen argon and carbon dioxid
Katena32 [7]
The correct answer is carbon dioxide and water vapor

These negative gasses get modified and then remain in the atmosphere without the possibility of leaving, which is why the greenhouse effect occurs.
7 0
2 years ago
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In the article "A Sea of Garbage" what message is each cartoon trying to convey to readers? Do they succeed?
sertanlavr [38]

Answer:

  1. yes in the article I see of garbage what's messages each carton trying to convey to your readers with a success obviously they do suck said they succeed because like that's really great day socks said is your garbage is like a pool of garbage work garbage are gathered together they are together a you get one talking about you know when cabbage and together they make efficient use of them okay I mean garbage garbage garbage garbage so I don't know I don't know I don't know I don't know I don't know but it's really is regret it regret it was someone couldn't wish for our young people pick them up and see if garbage and it's really not making sense cuz when you see a sea of garbage that means there's water in there and people pull up garbage in be like water pollution or something but I'm actually not really like sure but I have a slight idea of like what we talking about here right now and it's great
8 0
3 years ago
What is the silver ion concentration in a solution prepared by mixing 369 mL 0.373 M silver nitrate with 411 mL 0.401 M sodium c
LuckyWell [14K]

Answer:

[A g + ]  =  3.12 *10^-6 M

Explanation:

Step 1: Data given

Volume silver nitrate = 369 mL

Molarity silver nitrate = 0.373 M

Volume sodium chromate = 411 mL

Molarity sodium chromate = 0.401 M

The Ksp of silver chromate is 1.2 * 10^− 12

Step 2: The balanced equation

2 A g + ( a q )  +  C rO4^2-  ( a q )  →Ag2CrO4 (  s)

Step 3:

[Ag+]i = [AgNO3] * V1/(V1+V2) * 1 mol Ag+ / 1 mol AgNO3

[Ag+]i = 0.373 M * 0.369/ (0.369+0.411)

[Ag+]i = 0.176 M

[C rO4^2]i = [Ag2CrO4] * V2 /(V1+V2) * 1mol C rO4^2 / 1 mol Ag2CrO4

[C rO4^2i = 0.401 M * 0.411 / (0.369+0.411)

[C rO4^2]i = 0.211 M

Ksp = [Ag+]²[CrO4^2-] = 1.2 * 10^− 12

[CrO4^2-]f = [CrO4^2-]i - 0.5 * [Ag+]i

[CrO4^2-]f = 0.211 -0.088 = 0.123 M

1.2 * 10^− 12  = ( 2 x ) ²*( 0.123M + x )

[ C O 3^ −2] f  >>  x

1.2 * 10^− 12  = ( 2 x ) ²* 0.123M

x = 1.56 * 10^-6

[A g + ] f  = 2x = 3.12 *10^-6 M

,

4 0
3 years ago
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