All categories

3 years ago

Major arc definition

Mathematics

1 answer:

aliya0001 [1]3 years ago

4 0

Answer:

A major arc (right figure) is an arc of a circle having measure greater than or equal to ( radians). SEE ALSO: Arc, Minor Arc, Semicircle.

Step-by-step explanation:

You might be interested in

jake bought a shirt on sale for $80. The sale price of the shirt had been reduced by $40. What was the percent markdown on the s

Lorico [155]

The percent marked down on the shirt is 50%

5 0

3 years ago

Need help please anyone

kifflom [539]

Which question do you need help with

5 0

3 years ago

Solve for x : 4/5 x − 2 = 7

Sunny_sXe [5.5K]

Answer: x = 45/4

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the value of x that makes lines u and v parallel.

omeli [17]

Answer:

x = 5

Step-by-step explanation:

From the picture attached,

If the lines u and v are parallel and a third line (transversal) is intersecting these lines at two distinct points,

Both the angles given in the picture, will be equal in measure as these angles are interior alternate angles.

16x = 15x + 5

16x - 15x = 5

x = 5

Therefore, x = 5 makes the lines v and u parallel.

3 0

3 years ago

Please answer 26 and 27 please thank you

ser-zykov [4K]

Answer:

Part 26) $3\frac{1}{4}\ in$

Part 27) $2\frac{2}{3}\ cups$

Step-by-step explanation:

Part 26)

we know that

The length of Alana's hair was 9 3/4 inches

After her haircut, the length was 6 1/2 inches

To find out how many inches did she have cut subtract 6 1/2 from 9 3/4

but first

Convert mixed number to an improper fraction

$9\frac{3}{4}\ in=\frac{9*4+3}{4}=\frac{39}{4}\ in$

$6\frac{1}{2}\ in=\frac{6*2+1}{2}=\frac{13}{2}\ in$

Find the difference

$\frac{39}{4}-\frac{13}{2}=\frac{39-26}{4}=\frac{13}{4}\ in$

Convert to mixed number

$\frac{13}{4}\ in=\frac{12}{4}+\frac{1}{4}=3\frac{1}{4}\ in$

Part 27)

we have that

Emeril used a total of 7 1/4 cups of flour to make three pastries

He used 2 1/4 cup of flour for the first and 2 1/3 cups of flour for the second

To find out how much cups of flour Emeril use for the third pastry, subtract the sum of the cups of flour used in the first and second pastry from the total cups of pastry used

Let

x ----> number of cups of flour used in the third pastry

$x=7\frac{1}{4}-(2\frac{1}{4} +2\frac{1}{3})$

but first

Convert mixed number to an improper fraction

$7\frac{1}{4}\ in=\frac{7*4+1}{4}=\frac{29}{4}\ cups$

$2\frac{1}{4}\ in=\frac{2*4+1}{4}=\frac{9}{4}\ cups$

$2\frac{1}{3}\ in=\frac{2*3+1}{3}=\frac{7}{3}\ cups$

substitute

$x=\frac{29}{4}-(\frac{9}{4} +\frac{7}{3})$

$x=\frac{20}{4} -\frac{7}{3}$

$x=\frac{20*3-7*4}{12}$

$x=\frac{32}{12}\ cups$

Simplify

$x=\frac{8}{3}\ cups$

Convert to mixed number

$\frac{8}{3}=\frac{6}{3}+\frac{2}{3}=2\frac{2}{3}\ cups$

4 0

2 years ago