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lina2011 [118]
3 years ago
12

PLZ HELP

Chemistry
1 answer:
kompoz [17]3 years ago
3 0
The only two that apply is Oxygen and Water. The last one would be Carbohydrates.
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Which line segment on the graph represents boiling
hoa [83]
1. There is no graph given

2. ENERGY LEVELS!!!

Boiling is the process of liquid(middle energy, flat line) turning into a gas(lots of energy, flat line), hope this helps
8 0
4 years ago
(I ONLY HAVE 15 MIN LEFT IN MY TEST PLEASE HELP ME!!)
zloy xaker [14]

Answer:

183g

Explanation:

mass can't be created or destroyed so i think you just add up the total amounts of matter

8 0
3 years ago
What is the molar mass of the imaginary compound Z(AX3)2
astra-53 [7]

The molar mass of the imaginary compound Z(AX₃)₂ is the sum of the molar mass of Z, A and X.

<h3>How do we calculate molar mass?</h3>

Molar mass of any compound will be calculated by adding the mass of each atoms present in that compound.

Given compound is Z(AX₃)₂, molar mass of the given compound will be calculated as:

Molar mass of Z(AX₃)₂ = Molar mass of Z + molar mass of 2(A) + molar mass of 6(X)

Hence molar mass of Z(AX₃)₂ is the sum of the masses of all atoms.

To know more about molar mass, visit the below link:

brainly.com/question/18983376

#SPJ1

7 0
2 years ago
Pls help me ASAP thank you!!
Stolb23 [73]
Sorry i cant even read that
7 0
3 years ago
Suppose of barium acetate is dissolved in of a aqueous solution of ammonium sulfate. Calculate the final molarity of barium cati
ollegr [7]

Explanation:

Let us assume that the given data is as follows.

   mass of barium acetate = 2.19 g

   volume = 150 ml = 0.150 L    (as 1 L = 1000 ml)

   concentration of the aqueous solution = 0.10 M

Therefore, the reaction equation will be as follows.

        Ba(C_{2}H_{3}O_{2})_{2} \rightarrow Ba^{2+} + 2C_{2}H_{3}O^{-}_{2}

Hence, moles of C_{2}H_{3}O^{-}_{2} = 2 \times Ba(C_{2}H_{3}O_{2})_{2}  .......... (1)

As,   No. of moles = \frac{mass}{\text{molar mass}}

Hence, moles of Ba(C_{2}H_{3}O_{2})_{2} will be calculated as follows.                          

     No. of moles = \frac{mass}{\text{molar mass}}  

                          =  \frac{2.19 g}{255.415 g/mol}   (molar mass of Ba(C_{2}H_{3}O_{2})_{2} is 255.415 g/mol)            

                       = 8.57 \times 10^{-3}

    Moles of C_{2}H_{3}O^{-}_{2} = 2 \times 8.57 \times 10^{-3}

                          = 0.01715 mol

Hence, final molarity will be as follows.

              Molarity = \frac{\text{no. of moles}}{volume}

                             = \frac{0.01715 mol}{0.150 L}

                             = 0.114 M

Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.

5 0
3 years ago
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