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sweet-ann [11.9K]
3 years ago
8

What happens to the potassium atom when it reacts with the chlorine atom? What is the electron configuration of the potassium af

ter the change?
Chemistry
1 answer:
hodyreva [135]3 years ago
3 0

Answer:

See explanation

Explanation:

Potassium is a metal. Remember that metals are electropositive in nature. This implies that they give out electrons when they undergo ionic bonding with nonmetals.

Chlorine is a nonmetal. So the bond between chlorine and potassium is ionic.  Potassium gives out one electron to chlorine and the both ions now attain a stable octet.

The electronic configuration of potassium is [Ar]4s1. After giving out an electron to chlorine in an ionic bond, its electronic configuration is now [Ar].

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The Haber Process is the main industrial procedure to produce ammonia. The reaction combines nitrogen from air with hydrogen mai
Firdavs [7]

Answer:

A) N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g).

B) Kc=0.0933.

C) 0.9 mol.

D) Increasing both temperature and pressure.

Explanation:

Hello,

In this case, given the information, we proceed as follows:

A)

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

B) For the calculation of Kc, we rate the equilibrium expression:

Kc=\frac{[NH_3]^2}{[N_2][H_2]^3}

Next, since at equilibrium the concentration of ammonia is 0.6 M (0.9 mol in 1.5 dm³ or L), in terms of the reaction extent x, we have:

[NH_3]=0.6M=2*x

x=\frac{0.6M}{2}=0.3M

Next, the concentrations of nitrogen and hydrogen at equilibrium are:

[N_2]=\frac{1.5mol}{1.5L}-x=1M-0.3M=0.7M

[H_2]=\frac{4mol}{1.5L}-3*x=2.67M-0.9M=1.77M

Therefore, the equilibrium constant is:

Kc=\frac{(0.6M)^2}{(0.7M)*(1.77M)^3}\\ \\Kc=0.0933

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D) Here, since the reaction is endothermic (positive enthalpy change), one way to increase the yield of ammonia is increasing the temperature since heat is reactant for endothermic reactions. Moreover, since this reaction has less moles at the products, another way to increase the yield is increasing the pressure since when pressure is increased the side with fewer moles is favored.

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