To make 395 mL of a 0.630 M solution of HCI, how many mL of a 2.4 M solution should be used?
1 answer:
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Answer:
90.5mL is the volume of the gas at STP
Explanation:
It is possible to find volume of a gas when conditions of temperature and pressure change using combined gas law:
Where P is pressure, V is volume and T is absolute temperature. 1 is initial conditions and 2 final conditions.
If initial conditions are 1.08atm, 80.0mL and absolute temperature is (-12.5°C + 273.15) = 260.65K.
And STP are 1atm of pressure and 273.15K of absolute temperature. Replacing:
V₂ = <em>90.5mL is the volume of the gas at STP</em>
Answer:
6.460 gm is the correct answer .
Explanation:
Given
Kate’s blood volume=
blood glucose=
As we know that
The includes the blood glucose of the
So of the Kate’s blood volume can be determined by
To convert into the gm we have divided by the 1000
Therefore the glucose in her blood=
Answer:
The correct answer is 0.186 V
Explanation:
The two hemirreactions are:
Reduction: Fe²⁺ + 2 e- → Fe(s)
Oxidation : Co(s) → Co²⁺ + 2 e-
Thus, we calculate the standard cell potential (Eº) from the difference between the reduction potentials of cobalt and iron, respectively, as follows:
Eº = Eº(Fe²⁺/Fe(s)) - Eº(Co²⁺/Co(s)) = -0.28 V - (-0.447 V) = 0.167 V
Then, we use the Nernst equation to calculate the cell potential (E) at 298.15 K:
E= Eº - (0.0592 V/n) x log Q
Where:
n: number of electrons that are transferred in the reaction. In this case, n= 2.
Q: ratio between the concentrations of products over reactants, calculated as follows:
Finally, we introduce Eº= 0.167 V, n= 2, Q=0.2244, to obtain E:
E= 0.167 V - (0.0592 V/2) x log (0.2244) = 0.186 V