All categories

3 years ago

1. Describe the differences in the ways the sand castle is changed by an ocean wave and by Dylan stomping on it

1 answer:

6 0

A sand castle that was changed by the ocean waves would be slowly taken away from by the waves and would just become a smooth mound of sand. If Dylan stomped on it then it would still have all of the same sand as before but in a different shape. It would also become a mound of sand but it would have all the same sand as before.

(I don't know if I was supposed to talk about fancy physics stuff so I just gave a basic explanation. I don't know if my answer is really right or not... hope it helped though :))

You might be interested in

What is Secular Music's instrument's?

nasty-shy [4]

Answer:

Drums, harps, recorders, and bagpipes.

Explanation:

8 0

3 years ago

Heat transfer between two substances is affected by specific heat and the

Pie

<span>Heat transfer between two substances is affected by specific heat and the "Temperature difference between them"

Hope this helps!</span>

6 0

3 years ago

Read 2 more answers

Hydrogen fluoride gas (HF) and sodium hydroxide (NaOH) react in a test tube. They form water and sodium fluoride (NaF). Which ty

AfilCa [17]

This reaction is a double replacement reaction. Hydrogen in the hydrogen fluoride gets replaced by sodium of the sodium hydroxide. HF is a weak acid and NaOH is a strong base. So, double replacement produces sodium fluoride and water molecules.

6 0

3 years ago

Please help !!

nikitadnepr [17]

If the speed is constant, the acceleration a must be zero. Since force F = m•a, the total force must be zero.
In a 1D case, work W is the product of force F and distance d: W = F • d.
Since there is no more information given about friction or air resistance, I have to assume you are looking for the work done by the total force, wich is also zero.

3 0

3 years ago

Calculate the hang time of a person who moves 3 m horizontally during a 1.25-m high jump. What is the hang time when the person

jekas [21]

The duration of time for which an object stays in air is called the hang time.

For an athlete who moves 3m horizontally during a 1.25m high jump, the hang time will be the sum of the time taken by the athlete to reach the maximum height and the time taken for the athlete to reach the ground from maximum height.

Calculate the time taken t_1 by the athlete to reach the maximum height

$t_1 = \sqrt{\frac{2h}{g}}$

$t_1 = \sqrt{\frac{2(1.25)}{9.8}}$

$t_1 = 0.5s$

The athlete takes same time to reach the ground from the maximum height, so $t_2 = 0.5s$

Calculate the hang time will be

$t =t_1+t_2$

$t = 0.5+0.5$

$t = 1s$

Therefore the hang time of the athlete when he moves a horizontal distance of 3m is 1s.

Similarly, when the athlete runs 6m horizontally, then also there will not be a change in the hang time of the athlete as the hang time is independent of the horizontal distance covered.

4 0

3 years ago