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MakcuM [25]
3 years ago
14

Heat transfer between two substances is affected by specific heat and the

Physics
2 answers:
tigry1 [53]3 years ago
8 0

Answer: The heat transfer between two substances is affected by their specific heat and the difference in temperature between them.

Where the heat will flow from the substance with more temperature to the other, which means that if both substances have the same temperature, then there is no heat transfer,

Pie3 years ago
6 0
<span>Heat transfer between two substances is affected by specific heat and the "Temperature difference between them"

Hope this helps!</span>
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Prove law of conservation of energy for a stone moving vertically down ( explain energy at B &amp; C )
STALIN [3.7K]

As per given condition of point B we can see that height at point B is "h/2" from the ground

So we know that potential energy is given as

U = mgh

so here we have to put height h = h/2

so potential energy is U = mgh/2

now for kinetic energy we need to find the speed of it after falling the distance h/2

now by kinematics we will have

v_f^2 - 0^2 = 2(g)(h/2)

now for kinetic energy

KE = \frac{1}{2}mv^2 = \frac{1}{2}m(gh)

KE = 1/2mgh

now total energy will be given as

E = mgh/2 + mgh/2 = mgh

now for point C we can say that it is the point near to ground

So here height is ZERO

now potential energy will also be zero

U = 0

now for kinetic energy we need to find speed

v^2 - 0^2 = 2(g)(h)

now kinetic energy

KE = \frac{1}{2}mv^2 = \frac{1}{2}m(2gh)

KE = mgh

now again we have total energy

E = 0 + mgh = mgh

6 0
4 years ago
Two planets P1 and P2 orbit around a star S in circular orbits with speeds v1 = 40.2 km/s, and v2 = 56.0 km/s respectively. If t
Readme [11.4K]

Answer: 3.66(10)^{33}kg

Explanation:

We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity \omega of the planet P1 with a period T=750years=2.36(10)^{10}s:

\omega=\frac{2\pi}{T}=\frac{V_{1}}{R} (1)

Where:

V_{1}=40.2km/s=40200m/s is the velocity of planet P1

R is the radius of the orbit of planet P1

Finding R:

R=\frac{V_{1}}{2\pi}T (2)

R=\frac{40200m/s}{2\pi}2.36(10)^{10}s (3)

R=1.5132(10)^{14}m (4)

On the other hand, we know the gravitational force F between the star S with mass M and the planet P1 with mass m is:

F=G\frac{Mm}{R^{2}} (5)

Where G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

In addition, the centripetal force F_{c} exerted on the planet is:

F_{c}=\frac{m{V_{1}}^{2}}{R^{2}} (6)

Assuming this system is in equilibrium:

F=F_{c} (7)

Substituting (5) and (6) in (7):

G\frac{Mm}{R^{2}}=\frac{m{V_{1}}^{2}}{R^{2}} (8)

Finding M:

M=\frac{V^{2}R}{G} (9)

M=\frac{(40200m/s)^{2}(1.5132(10)^{14}m)}{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}} (10)

Finally:

M=3.66(10)^{33}kg (11) This is the mass of the star S

4 0
4 years ago
Which is the best evidence that continents that are now separated were once
Rasek [7]
I’d say It’s B since the plants and fossils are big indicators
3 0
3 years ago
Read 2 more answers
The Newton is the SI unit for ____.<br> temperature<br> mass<br> weight<br> density
mel-nik [20]

Answer:

weight

Explanation:

weight is measurd in newtons (N)

7 0
3 years ago
How much power does an Ox pulling a plow 20 m cross a field, exerting 120J of work over a period of 15 s?​
Aleksandr-060686 [28]

Answer:

8W

Explanation:

Given parameters:

Distance covered  = 20m

Work done  = 120J

Time  = 15s

Unknown:

How much power does the Ox exerts  = ?

Solution:

Power is the rate at which work is being done

  Power  = \frac{Work done }{time}  

 Power exerted by ox  = \frac{120}{15}   = 8W

3 0
3 years ago
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