As per given condition of point B we can see that height at point B is "h/2" from the ground
So we know that potential energy is given as
U = mgh
so here we have to put height h = h/2
so potential energy is U = mgh/2
now for kinetic energy we need to find the speed of it after falling the distance h/2
now by kinematics we will have

now for kinetic energy


now total energy will be given as

now for point C we can say that it is the point near to ground
So here height is ZERO
now potential energy will also be zero
U = 0
now for kinetic energy we need to find speed

now kinetic energy


now again we have total energy

Answer: 
Explanation:
We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity
of the planet P1 with a period
:
(1)
Where:
is the velocity of planet P1
is the radius of the orbit of planet P1
Finding
:
(2)
(3)
(4)
On the other hand, we know the gravitational force
between the star S with mass
and the planet P1 with mass
is:
(5)
Where
is the Gravitational Constant and its value is 
In addition, the centripetal force
exerted on the planet is:
(6)
Assuming this system is in equilibrium:
(7)
Substituting (5) and (6) in (7):
(8)
Finding
:
(9)
(10)
Finally:
(11) This is the mass of the star S
I’d say It’s B since the plants and fossils are big indicators
Answer:
weight
Explanation:
weight is measurd in newtons (N)
Answer:
8W
Explanation:
Given parameters:
Distance covered = 20m
Work done = 120J
Time = 15s
Unknown:
How much power does the Ox exerts = ?
Solution:
Power is the rate at which work is being done
Power =
Power exerted by ox =
= 8W