What is Secular Music's instrument's?
1 answer:
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Answer: 8.8 m
Explanation:
The movement of the baseball to the wall is a example of parabolic motion. While the baseball aproach the wall it is affected by gravity.
In this case, because the Initial Velocity of the ball is a vecotr, it can be defined using its two directionals compounds. One, on the Y-axis and another on the X-axis. This can be related, on how a hypotenuse is the product of two legs of the triangle. Because of this, each one of this, can be know using the following equation:
Vx = Vo * cos(∅)
Vy = Vo * sin(∅)
Where Vo is the initial velocity 27.5 m/s, and ∅ is the angle which is 20.5°. So we calculate:
Vx = 27.5m/s * cos(20.5)
Vx = 27.5m/s * 0.936
Vx = 25.74m/s
Vy = 27.5m/s * sin(20.5)
Vy = 27.5m/s * sin(20.5)
Vy = 9.62m/s
Now the movement is divided on two parts, one under the effect of gravity and another one with a constant velocity.
To know how tall does the baseball hit the wall, we need to know first how much time it takes the ball to reach the wall on the X-axis. The wall is 17.5m away, we velocity on Vx that is constant we can calculate as it follow:
Time (T) = Distance (D) / Velocity (V)
Where Distance is 17.5m and our Velocity is the Vx calculated before.
T = 17.5 m / 25.74m/s
T = 0.68s
This is the time it takes the ball to reach the wall.
Know with the time, we can calculate the how tall it got on that time with the following equation:
Where Vo is the Y-Compound of the Initial Velocity.
a is the aceleration, in this case the Gravity. Which, will be negative because is oposing the movement. Gravity is equal to 9.81
And t is the time it takes the ball to get to the wall.
This is the height that the baseball touch the wall.
Answer:
Explanation:
<u>Horizontal Launch </u>
It happens when an object is launched with an angle of zero respect to the horizontal reference. It's characteristics are:
- The horizontal speed is constant and equal to the initial speed
- The vertical speed is zero at launch time, but increases as the object starts to fall
- The height of the object gradually decreases until it hits the ground
- The horizontal distance where the object lands is called the range
We have the following formulas
Where is the initial horizontal speed,
is the vertical speed, t is the time, g is the acceleration of gravity, x is the horizontal distance, and y is the height.
If we know the initial height of the object, we can compute the time it takes to hit the ground by using
Rearranging and solving for t
We then replace this value in
To get
The initial speed depends on the initial height y=32.5 m, the range x=107.6 m and g=9.8 m/s^2. Computing
The launch velocity is
D -
You basically keep varying the coefficient so until the number of atoms for each element is equal. I started with iron to show how you might have to change coefficients but it would be more efficient and quicker to start with oxygen since it changes the value or iron required.
You basically keep varying the coefficient so until the number of atoms for each element is equal. I started with iron to show how you might have to change coefficients but it would be more efficient and quicker to start with oxygen since it changes the value or iron required.