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3 years ago

Which of the following is a polynomial with roots: − square root of 3, square root of 3, and −2?

Mathematics

1 answer:

Tom [10]3 years ago

4 0

If I'm not mistaken it would be b.

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X/4 - x/6 = 1<br><br> please help

Archy [21]

To solve this multiply through by the LCM of 4 and 6, which is 12:-

12 * x/4 - 12 * x/6 = 1*12

3x - 2x = 12

x = 12 answer

4 0

3 years ago

Students in the school band are selling calendars they earn 0.40 on each calendar They sell. Their goal is to earn more than 327

Alexxandr [17]

Answer:

130.8

Step-by-step explanation:

i just think that you times 0.40 and 327 and then press = and it should give you 130.8

i hope it works

5 0

3 years ago

Rational formulas and variations

Zanzabum

Answer:

Direct to running

Joint to apples

Direct to meat

I hope this is good enough:

7 0

3 years ago

Cubed root x cubed root x2

Yuki888 [10]

Answer:

Final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

Step-by-step explanation:

Given problem is $\sqrt[3]{x}\cdot\sqrt[3]{x^2}$ .

Now we need to simplify this problem.

$\sqrt[3]{x}\cdot\sqrt[3]{x^2}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}$

Apply formula

$\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}$

so we get:

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$

Hence final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

7 0

3 years ago

The speed of water in a whirlpool varies inversely with the radius. If water speed is 2.5 feet per second at a radius of 30 feet

Nata [24]

The speed of the water in the 3 feet radius is 25 feet per second.

4 0

3 years ago

Read 2 more answers