If tan0=-3/4 and 0 is in quadrant IV, cos20= (33/25, -17/25, 32/25, 7/25, 24/25?) and tan20= (24/7, -24/7, 7/25, -7/25, 13/7, -1
Oksana_A [137]
Answer:
- cos(2θ) = 7/25
- tan(2θ) = -24/7
Step-by-step explanation:
Sometimes, it is easiest to let a calculator do the work. (See below)
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The magnitude of the tangent is less than 1, so the reference angle will be less than 45°. Then double the angle will be less than 90°, so will remain in the 4th quadrant, where the cosine is positive and the tangent is negative.
You can also use the identities ...
cos(2θ) = (1 -tan(θ)²)/(1 +tan(θ)²)
cos(2θ) = (1 -(-3/4)²)/(1 +(-3/4)²) = ((16-9)/16)/((16+9)/16)
cos(2θ) = 7/25
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tan(2θ) = 2tan(θ)/(1 -tan(θ)²) = 2(-3/4)/((16-9/16) = (-6/4)(16/7)
tan(2θ) = -24/7
Answer:
g(f(4)) = -3
Step-by-step explanation:
f(x)=x-7
g(x) = x
g(f(4))
f(4) = 4-7
f(4) = -3
g(-3) = -3
16 x 8 = 128 square feet (area of rectangle)
shaded:
8 x 2 = 16
10 x 1 = 10
1/2 (3)(10) = 15
total shaded area: 16+10+15 = 41 square feet
total non-shaded area = 128 - 41 = 87 square feet
answer
area of the shaded region = 41 square feet
area of the non - shaded region = 87 square feet
7=4w+19
7-19 = 4w+19-19
-12 = 4w
-12/4 = 4w/4
-3 = w
Answer:
(3 x 10^6) + (3 x 10^5) + (7 x 10^4) + (0 x 10^3) + (0 x 10^2) + (6 x 10^1)
Step-by-step explanation: