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Dmitry_Shevchenko [17]

3 years ago

10

The drama teacher decreased the length of a play from 90 minutes to 60 minutes what was the percent decrease in length of the pl

ay?

1 answer:

sveticcg [70]3 years ago

7 0

15% should be your answer.... I hoped this helped!!!!

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Which statement is true about the equations –3x + 4y = 12 and 1/4x –1/3 y = 1?The system of the equations has exactly one soluti

iren [92.7K]

Answer:

The system of the equations has no solution; the two lines are parallel.

Step-by-step explanation:

The equations have the same slope. In standard form, this can be seen as the same coefficients for x and y. We will multiply the second equation by -12 to reveal this.

$\frac{1}{4} x-\frac{1}{3}y=1 \\-12(\frac{1}{4} x-\frac{1}{3}y=1)\\\frac{-12}{4} x-\frac{-12}{3}y=-12\\-3x+4y=-12$

This means the equations are parallel and will never cross. There is no solution.

4 0

3 years ago

Find the two points on segment AB that divide the segment into 3 congruent Parts if A has coordinates (0 0) and point B has coor

Elena L [17]

Answer:

(3, 2), (6, 4)

Step-by-step explanation:

Since one end (A) of the segment AB is at the origin, the required points will be 1/3 and 2/3 of the coordinates of B:

(1/3)(9, 6) = (3, 2)

(2/3)(9, 6) = (6, 4)

8 0

3 years ago

In a box there are three types of chocolate. there are 6 plain chocolate 8 milk chocolate and 10 white chocolate. Deon takes 2 c

olchik [2.2K]

Step-by-step explanation:

1 plain chocolate and 1milk chocolate
1 plain chocolate and 1 white chocolate
1 milk chocolate and 1 white chocolate

<h3>we have to it like that only right??</h3>

8 0

3 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago

David had a bunch of grapes for his snack . If he at 0.1 of a pound every hour , how many pounds did he eat in a 4.4 hours ?

olga_2 [115]

0.44 lbs.
Is likely your answer

8 0

3 years ago

Read 2 more answers