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Y_Kistochka [10]
3 years ago
5

What is the mass of 1.84 mol NaCl? Give your

Chemistry
2 answers:
dusya [7]3 years ago
5 0

Answer:

The answer is 108 g NaCI

Explanation:

snow_tiger [21]3 years ago
4 0

Answer:

108 g

Explanation:

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If 75.0% of the isotopes of an element have a mass of 35.0 amu and 25.0% of the isotopes have a mass of 37.0amu what is the atom
Norma-Jean [14]
 <span>Calculating average atomic mass is exactly like calculating a weighted average. Perform the following calculation: 

(mass1)(percentage1) + (mass2)(percentage2) = average atomic mass 

(35.0)(0.75) + (37.0)(0.25) = average atomic mass 

Make sure your percentages are in decimal form for this calculation. 

One of the other answers given is correct, though the explanation is lacking a bit. Two of the answers can be eliminated immediately: 35.0 amu and 37.0 amu cannot be the average. If the mixture of isotopes was 50% and 50%, then 36.0 amu would be correct; however, the mixture is 75/25. This leaves only one possible answer choice.</span>
8 0
4 years ago
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a new weight-loss fad claims that you can reduce your mass simply by traveling to the Moon where gravity is weaker. why is this
Lilit [14]
Your mass can never change no matter where you are since mass is the amount of matter you contain.  By going to the moon, you do become lighter due to the weaker gravity but the amount of matter that you are made of (your mass) does not change.

I hope the helps.  Let me know if anything is unclear.
3 0
3 years ago
PLEASE HELP! Find out whether the chemical equation is balanced or unbalanced.
nordsb [41]

One chemical reaction is called the Haber process, a method for preparing ammonia by reacting nitrogen gas with hydrogen gas:


This equation shows you what happens in the reaction, but it doesn’t show you how much of each element you need to produce the ammonia. To find out how much of each element you need, you have to balance the equation — make sure that the number of atoms on the left side of the equation equals the number of atoms on the right.


You know the reactants and the product for this reaction, and you can’t change them. You can’t change the compounds, and you can’t change the subscripts, because that would change the compounds.


So the only thing you can do to balance the equation is add coefficients, whole numbers in front of the compounds or elements in the equation. Coefficients tell you how many atoms or molecules you have.


For example, if you write the following, it means you have two water molecules:


Each water molecule is composed of two hydrogen atoms and one oxygen atom. So with two water molecules (represented above), you have a total of 4 hydrogen atoms and 2 oxygen atoms.


You can balance equations by using a method called balancing by inspection. You take each atom in turn and balance it by adding appropriate coefficients to one side or the other.


With that in mind, take another look at the equation for preparing ammonia: HOPE THIS HELPS



4 0
3 years ago
Briefly summarise the death of Jesus Christ​
salantis [7]

Answer:

The death of Jesus was a unique, one of a kind, once for all death that ransomed mankind from sin and satisfied the righteousness of God and made it possible for man to once again have a personal relationship with God. The simple definition of death is separation.

Explanation:

hope this helps? :))

4 0
3 years ago
Read 2 more answers
Calculate the concentration of hydroxide ions (OH-) in a solution with a pOH of 2.52?
vodomira [7]

Answer:

The concentration of hydroxide ions is 3.02*10⁻³ M

Explanation:

The pOH (or OH potential) is a measure of the basicity or alkalinity of a contamination and is defined as the negative logarithm of the activity of the hydroxide ions. That is, the concentration of OH- ions:

pOH= -log [OH-]

The pOH has a value between 0 and 14 in aqueous solution, the solutions with pOH being greater than 7 being acidic, and those with pOH less than 7 being basic.

If pOH= 2.52 then

2.52= -log [OH-]

[OH-]= 3.02*10⁻³ M

<u><em>The concentration of hydroxide ions is 3.02*10⁻³ M</em></u>

<u><em></em></u>

3 0
3 years ago
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