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dusya [7]
3 years ago
11

Based on the spectrum observed for incandescent white light, rank the colors in the visible spectrum from highest energy to lowe

st energy

Chemistry
1 answer:
SOVA2 [1]3 years ago
8 0

Answer:

See below.  

Step-by-step explanation:

An incandescent lamp produces all colours of the visible spectrum, with wavelengths ranging from approximately 400 nm (violet) to 700 nm (red).

Since <em>energy is inversely proportional to wavelength</em>,

E ∝ 1/λ

a quantum of 400 nm violet light has more energy than one of 700 nm red light.

An incandescent lamp produces a relatively small amount of the high-energy blue/violet light ( see image below).

The table below gives the colours in the visible spectrum, ranked from highest to lowest energy.

<u>Colour        λ/nm       </u>

Violet      400 – 450

Blue        450 – 490

Cyan       490 – 520

Green     520 – 560

Yellow    560 – 590

Orange  590 – 635

Red        635 – 700

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3 years ago
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6 0
4 years ago
Assuming that the experiments performed in the absence of inhibitors were conducted by adding 5 μl of a 2 mg/ml enzyme stock sol
prohojiy [21]

Hey there!:

From the given data ;

Reaction  volume = 1 mL , enzyme content = 10 ug ( 5 ug in 2 mg/mL )

Enzyme mol Wt = 45,000 , therefore [E]t is 10 ug/mL , this need to be express as "M" So:

[E]t in molar  = g/L * mol/g

[E]t  = 0.01 g/L * 1 / 45,000

[E]t = 2.22*10⁻⁷

Vmax = 0.758 umole/min/ per mL

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Therefore :

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Hope that helps!



4 0
3 years ago
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