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Ilia_Sergeevich [38]
3 years ago
10

How to solve linear and nonlinear equations graphically?

Mathematics
1 answer:
Ede4ka [16]3 years ago
8 0
Plot the equation. If you wish to solve a polynomial, let y= polynomial and plot the graph. Best set up a table of values first.
Where the graph crosses the x axis there is a solution for x. There are also solutions for other horizontal lines (y values) by looking at intersections of the graph with these lines. This technique works for linear and non linear equations. You can also use graphs to solve 2-variable systems of equations by examining where the graphs intersect one another. The disadvantage is that you may not be able to have sufficient detail for high degrees of accuracy because of the scale of the graph and drawing inaccuracies.
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HELP ME PLEASE I RELOADED IT AND IT GAVE ME ANOTHER QUESTION IM GONNA CRY
Murljashka [212]
It would be 4x^2+11x-3
Or the far bottom right corner
7 0
2 years ago
Read 2 more answers
How many times does eight go into 20
Mademuasel [1]
<h3><u>Eight can only go into 20 </u><u>two </u><u>full times.</u></h3>

8 * 2 = 16

16 + 8 = 24 ≠ 20

4 0
3 years ago
The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is the greatest possible v
andre [41]
Q2. The answer is <span>D. 2w + 2 • (3w) ≤112
</span>
The perimeter of a rectangle is: P = 2w + 2l         (w - weight, l - length)
<span>
The perimeter is at most 112 centimeters: P </span>≤ 112
<span>The length of a rectangle is three times its width: l = 3w

</span>P ≤ 112
2w + 2l ≤ 112

l = 3w
2w + 2 * (3w) ≤ 112



Q2.2. The answer is <span>D. 8 cm
</span>
The perimeter of a rectangle is: P = 2w + 2l         (w - weight, l - length)

<span>The length of a rectangle is five times its width: l = 5w
</span><span>The perimeter is at most 96 centimeters: P </span>≤ 96

P ≤ 96
2w + 2l ≤ 96

l = 5w
2w + 2 * 5w ≤ 96
2w + 10w ≤ 96
12w ≤ 96
w ≤ 96 : 12
w ≤ 8 cm
7 0
3 years ago
Read 2 more answers
The line (x, y, z) = (1 − 2t, 2t − 1, t), with t as the parameter, is denoted by L. The point Q is (1, 2, 3).
inessss [21]

Answer:

P = (-1,1,1)

Step-by-step explanation:

for the line

L (t) = (1 − 2t, 2t − 1, t)

since the vector that is tangent to L is its derivative L'=dL/dt , then

L'= dL/dt (t) =  (−2, 2 , 1)

then the vector PQ (P to Q) is

PQ = (x,y,z) - (1, 2, 3) = ( x-1 , y-2 ,z-3)

since P belongs to L → x= 1-2t . y=2t-1 and z=t ,

PQ =  ( x-1 , y-2 ,z-3) = (-2t , 2t-3 , t-3)

to be ortogonal to L , PQ should be ortogonal to L' , then the dot product between PQ and L should be 0

PQ * L' = 0

(-2t , 2t-3 , t-3)* (−2, 2 , 1) =0

4t + (4t-6) + (t-3) = 0

9t - 9= 0

t = 1

then

P = L(t=1) = ( 1-2*1 , 2*1-1 , 1 ) = (-1,1,1)

P = (-1,1,1)

5 0
3 years ago
A? twin-engined aircraft can fly 1064 miles from city A to city B in 4 hours with the wind and make the return trip in 7 hours a
sashaice [31]

Answer:

Wind speed = 159.6 miles per hour.

Step-by-step explanation:

The distance is the same so some sort of basic equation can be made.

Givens

From A to B

t = 4 hours

v = p + w

d = 1064

===========

From B to A

t1 = 7 hours

v = p - w

d = 1064

Equation

t * (p + w) = t1 * ( p - w)

Solution

4(p + w) = 7(p - w)

4p + 4w = 7 p - 7w

<em>Add 7w to both sides</em>.

4p + 4w + 7w = 7p

4p + 11w = 7p    

<em>Subtract 4p from both sides</em>

11w = 7p - 4p

11w = 3p

<em>Divide by 3</em>

p = 11w/3

====================

4P + 4W = 1064

11w/3 + 3W = 1064

w(3.6667 + 3) = 1064

W*6.666667 = 1064

W = 1064 / 6.666667

W = 159.6 mph

4 0
3 years ago
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