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3 years ago

Reduce then calculate 7/8 x 4/15 x 3/7 = ? Can you help?

1 answer:

8 0

since this is a multiplication, all the numerators are just factors of the product numerator and all denominators are just factors of the product denominator, so we can simply reorder them some, without changing the product.

$\bf \cfrac{7}{8}\times \cfrac{4}{15}\times \cfrac{3}{7}\implies \cfrac{7}{7}\times \cfrac{4}{8}\times \cfrac{3}{15}\implies \cfrac{1}{1}\times \cfrac{1}{2}\times \cfrac{1}{5}\implies \cfrac{1\cdot 1\cdot 1}{1\cdot 2\cdot 5}\implies \cfrac{1}{10}$

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X2-12x+20 anyone? help plz

Leto [7]

The answer is -10x+20

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3 years ago

1.5 as a mixed number and 1.5 as a improper fraction

sergey [27]

1.5 as a mixed muber is 1 and 1/2, as an improper fraction it could be 3/2

5 0

3 years ago

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Suppose I have an urn with 9 balls: 4 green, 3 yellow and 2 white ones. I draw a ball from the urn repeatedly with replacement.

Mrrafil [7]

Answer:

$E(X_n)=\frac{2(n-1)}{27}$

$E(y)=\frac{14}{9}$

Step-by-step explanation:

From the question we are told that:

Sample size n=9

Number of Green $g=4$

Number of yellow $y=4$

Number of white $w=4$

Probability of Green Followed by yellow P(GY) ball

$P(GY)=\frac{4}{9}*\frac{3}{9}$

$P(GY)=\frac{4}{27}$

Generally the equations for when n is even is mathematically given by

$Probability of success P(S)=\frac{4}{27}$

$Probability of Failure P(F)=\frac{27-4}{27}$

$Probability of Failure P(F)=\frac{23}{27}$

Therefore

$E(X_n)=\frac{n}{2}*P$

$E(X_n)=\frac{n}{2}*\frac{4}{27}$

$E(X_n)=\frac{2n}{27}$

Generally the equations for when n is odd is mathematically given by

$\frac{n-1}{2}$

$E(X_n)=\frac{n-1}{2}*\frac{4}{27}$

$E(X_n)=\frac{2(n-1)}{27}$

Probability of drawing white ball

$P(w)=\frac{2}{9}$

Therefore

$E(w)=\frac{1}{p}$

$E(w)=\frac{1}{\frac{2}{9}}$

$E(w)=\frac{9}{2}$

Therefore

$E(y)=[E(w)-1]\frac{4}{9}$

$E(y)=[\frac{9}{2}-1]\frac{4}{9}$

$E(y)=\frac{14}{9}$

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3 years ago

Write an algebraic expression that models the following statement:

koban [17]

Answer:

4(x+7)

or 4x+28

Step-by-step explanation:

Here you go:)

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2 years ago

Julie gives 7 pieces of candy to each of her friends. If Julie gives all of her candy away, which amount of candy could have bee

True [87]

To find the answer to this problem, you just need to figure out which total amount of candy is divisible by 7.

161/7=23
162/7=23.1428571429
145/7=20.7142857143
128/7=18.2857142857

Obviously, Julie cannot give a fraction of an amount of candy to someone. So that rules out that she had 162, 145, or 128 pieces of candy.

The only amount of candies that Julie could have that is divisible by 7 is 161 candies, which means that 161 is your answer.

5 0

3 years ago

Read 2 more answers