A=2
4*2=8+1=9/////2+7=9
both of the answers are 9, so a=2
This is pretty simple once you figure out the trick.
All you have to do is make the args common.
Meaning
is nothing but 
Which is nothing but:
.
Now using the scorpion tail method, this equation can be reframed to being:
. You bring 6 to the other side and it'll become: 
Factorise it and you get: 
Henceforth, the solution would be
and
. :D
Answer:

Step-by-step explanation:

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have

Therefore, the probability of event A is given by

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Answer:
75%
Step-by-step explanation:
There are 6 numbers that fit the rule, 1, 2, 3, 4, 6, 8. Since there are a total of 8 numbers, there is a 6/8 chance picking one or 75% chance.