An equation of line with a slope of 1/3 and containing the point (-4,7) is
y = 1/3 x + 25/7
In this question, we have been given
slope (m) = 1/3
and a point (-4, 7)
We need to find an equation of a line with a slope of 1/3 and containing the point (-4,7)
Using the formula for the slope-point form of equation of line,
y - y1 = m(x - x1)
y - 7 = 1/3(x + 4)
y - 7 = (1/3)x + 4/3
y = (1/3)x + 4/3 + 7
y = 1/3 x + 25/7
Therefore, an equation of line with a slope of 1/3 and containing the point (-4,7) is y = 1/3 x + 25/7
Learn more about the equation of line here:
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Answer:
The slope intercept is y=mx+b
y=-1x (you go down one over one from your y-intercept)
y=-1x-1 (It would be minus one because that is where it crosses the y-axis)
Step-by-step explanation:
The answer is 9 and 5. This is because when you add 9 and 5, you get 14. Also, when you multiply those 2 numbers, the product is 45. Hope this helped!!!!!!!!!!!!!!!!!
Answer: 155x or put 25x
Step-by-step explanation:
20x + 5x = 25x , 180 - 25x = 155x
use four angles and add but keep the x
only do the two sides of the angle
Answer:
the correct answer is 10.1 on the goggle forms it is 10
Step-by-step explanation:
0.1 multiplied by 101 is 10.1