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lora16 [44]
3 years ago
14

A rectangular field has an area 28800 sq meter. Its length is twice as long as its width. What is the length of its sides?

Mathematics
1 answer:
mina [271]3 years ago
3 0
W= width L= length = 2W

Area of Rectangle= Length * Widthsubstitute the area and the value of L in the formula
28,800 m^2= 2W * W
28,800= 2W^2divide both sides by 2 in an effort to isolate the variable w
14,400= W^2take the square root of both sides
√14,400= W^2
we want the negative and positive root of the radicand (the number under the radical symbol - 14,400 in this case)
120= w OR -120= w


LENGTHL= 2W= 2(120)= 240 meters

ANSWER: The side lengths are W= 120 m; L= 240 m.  Even though W= -120 too, it is not a valid solution in this case since a field cannot have a negative value.

Hope this helps!  :)
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Answer:

The required recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

Step-by-step explanation:

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Each year thereafter the number of leaves was 40% more than the year before so that means

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For the third year the number of leaves increase 40% than the year before so that means

Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\

Similarly for fourth year,

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So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330

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