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Darya [45]
4 years ago
7

RSM PROBLEM NEED HELP!!!!!!11If a grocer mixed 3 lbs of candy costing $1.7 per pound and 5 lbs of candy costing 90 cents per pou

nd, what should the price of the mixture be?
Mathematics
1 answer:
Sergio [31]4 years ago
5 0

The total price of the mixture of the candies = $ 5.1 + $ 4.5 = $ 9.6

<u>Step-by-step explanation:</u>

Cost of 1 pound of 1st type of candy = $ 1.7

Weight of 1st type of candy = 3 lbs

So the total cost 3 lbs of the 1st type of candy = 3 × $ 1.7 = $ 5.1

Cost of 1 pound of 2nd type of candy = 90 cents = $ 0.9

Weight of 2nd type of candy = 5 lbs

So the total cost 5 lbs of 2nd type of candy = 5 × $ 0.9 = $ 4.5

Since the grocer mixed the two types of candies,  

The total price of the mixture of the candies = $ 5.1 + $ 4.5 = $ 9.6

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which of the following best describes 4^2/3? a. sq root of 16, b. cube root of 4, c. sq root of four, d. cube root of 16
son4ous [18]

Answer: D) cube root of 16

================================================

Explanation:

The rule we use is

x^{m/n} = \sqrt[n]{x^m}

In this case, x = 4, m = 2 and n = 3.

So,

x^{m/n} = \sqrt[n]{x^m}\\\\\\4^{2/3} = \sqrt[3]{4^2}\\\\\\4^{2/3} = \sqrt[3]{16}\\\\\\

Showing that the original expression turns into the cube root of 16.

4 0
3 years ago
Current rules for telephone area codes allow the use of digits​ 2-9 for the first​ digit, and​ 0-9 for the second and third​ dig
Anna35 [415]

Using the fundamental counting theorem, we have that:

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The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.

For the area code:

  • 8 options for the first digit.
  • 9 options for the second and third.

Thus:

8 \times 9 \times 9 = 648

648 different area codes are possible with this rule.

For the number of 10-digit phone numbers:

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Then

648 \times 10^7 = 6,480,000,000&#10;

There are 6,480,000,000 possible 10-digit phone numbers.

The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

A similar problem is given at brainly.com/question/24067651

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3 years ago
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32 models need to make model of 3200.

Given that a 1 model contain 100.

Two series of numbers, usually empirical data, that are proportional or proportional if their respective elements are in constant proportion, called the scaling factor or the rate constant.

One model has 100 elements.

Now, we have to find how many model contains 3200 elements.

So, 1 model=100 elements

n model =3200 elements

We will write this in proportion as

1/n=100/3200

Applying the cross multiply, we get

3200×1=n×100

Divide both sides with 100, we get

3200/100=100n/100

3200/100=n

32=n

Hence, the  32 models contain 3200 elements when one contain 100 elements.

Learn more about proportional from here brainly.com/question/23536327

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