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Katyanochek1 [597]
1 year ago
6

How many models of 100 do you need to model 3200 explain ​

Mathematics
1 answer:
rusak2 [61]1 year ago
4 0

32 models need to make model of 3200.

Given that a 1 model contain 100.

Two series of numbers, usually empirical data, that are proportional or proportional if their respective elements are in constant proportion, called the scaling factor or the rate constant.

One model has 100 elements.

Now, we have to find how many model contains 3200 elements.

So, 1 model=100 elements

n model =3200 elements

We will write this in proportion as

1/n=100/3200

Applying the cross multiply, we get

3200×1=n×100

Divide both sides with 100, we get

3200/100=100n/100

3200/100=n

32=n

Hence, the  32 models contain 3200 elements when one contain 100 elements.

Learn more about proportional from here brainly.com/question/23536327

#SPJ9

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4 0
2 years ago
Thank you!!!!!!!!!!!!!!!
OverLord2011 [107]

Answer:

Binomial distribution requires all of the following to be satisfied:

1. size of experiment (N=27) is known.

2. each trial of experiment is Bernoulli trial (i.e. either fail or pass)

3. probability (p=0.14) remains constant through trials.

4. trials are independent, and random.

Binomial distribution can be used as a close approximation, with the  usual assumption that a sample of 27 in thousands of stock is representative of the population., and is given by the probability of x successes (defective).

P(x)=C(N,x)*p^x*(1-p)^(n-x)

where N=27, p=0.14, and C(N,x) is the number of combinations of x items out of N.

So we need the probability of <em>at most one defective</em>, which is

P(0)+P(1)

= C(27,0)*0.14^0*(0.86)^(27) + C(27,1)*0.14^1*(0.86^26)

=1*1*0.0170 + 27*0.14*0.0198

=0.0170+0.0749

=0.0919


4 0
3 years ago
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